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3 years ago

The following points are on the graph of a function:

Mathematics

1 answer:

Maurinko [17]3 years ago

5 0

An inverse function reverses the roles of inputs and outputs (of x-values and y-values).

If (2,4) is on the graph of a function, then (4,2) is on the graph of the inverse function.

If (9,7) is on the graph of the inverse, then (7,9) would be on the graph of the original function.

If (a,b) is on the graph of the function, then (b,a) is on the graph of the inverse.

Getting to your question, which of the points listed has the inverse listed up in the table?

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A rectangle has a length of (x + 4) centimeters and a width of 12x centimeters. If the perimeter is 26 centimeters, what is the

mars1129 [50]

Width of rectangle is 8.4 cm

Step-by-step explanation:

Length of rectangle = x+4

Width of rectangle = 12x

Perimeter = 26 cm

We need to find width of rectangle.

The formula used is:

$Perimeter=2(length+width)$

Putting values and finding x first:

$Perimeter=2(length+width)$

$26=2(x+4+12x)$

$26=2(13x+4)$

$26=26x+8$

$26-8=26x$

$26x=18$

$x=\frac{18}{26}$

$x=0.7$

So, value of x is 0.7

Now width= 12x = 12(0.7)

=8.4 cm

So, width of rectangle is 8.4 cm.

Keywords: Perimeter of Rectangle

Learn more about perimeter of rectangle at:

#learnwithBrainly

5 0

3 years ago

HELLLPPPPP PLLLLZZZZZZZ

koban [17]

I had that question yesterday

8 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago

Please please help me and fast

Eduardwww [97]

Its 12. Part a was 2 part b was 3
6×2=12
4×3=12

4 0

3 years ago

Calculate the tenth term for n + 3<br> (n + 3)

rewona [7]

Answer:

10 + 3 = 13

Step-by-step explanation:

I hope it's ryt

3 0

3 years ago