The following points are on the graph of a function:
1 answer:
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ANSWER
See attachment
EXPLANATION
The given inequality is
This implies that,
Multiply both sides of the second inequality by -1 and reverse the inequality sign.
The graphical solution to this inequality is shown in the attachment.
See attachment
EXPLANATION
The given inequality is
This implies that,
Multiply both sides of the second inequality by -1 and reverse the inequality sign.
The graphical solution to this inequality is shown in the attachment.
Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:
As h approaches 0 from the positive side, then:
Thus, f'(c) = 0
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:
As h approaches 0 from the positive side, then:
Thus, f'(c) = 0