Answer:
26
Step-by-step explanation:
JKL= ABC, jkl=abc
1.) use law of sines to find k.

2.) use law of cosines to find L
plug in for b and c: 
cross multiply: 

L=26
Answer:
Then, the object will take 29.11 min to travel 
Step-by-step explanation:
When an object is moving at a steady speed, we can calculate the time it would take to travel a given distance using the following formula:
(equation 1)
In this particular, both the given speed and distance are mixed fractions so we'll first convert them into improper fractions to operate more easily:


So, now we can calculate the time using the equation 1:


And, if we want the result in minutes:

Then, the object will take 29.11 min to travel 
Step-by-step explanation:
Given
(2x - 7) ²
We can see it is in the form of (a - b) ² so.
= (2x)² - 2 * 2x * 7 + 7²
= 4x² - 28x + 49
The best way to solve this is to make an algebraic expression to represent the situation~
If x is the speed of the first train and y is the speed of the second we can make 716.7 = x + y
the first train is 5.3 mph faster so x = y + 5.3
Now we can replace x with our new value to get 716.7 = y + (y+5.3)
Simplify and we get 716.7 = 2y + 5.3
Now all we got to do is simplify this equation, 716.7 - 5.3 = 711.4. Divide by 2 to get 355.7 for the speed of the second train. Since the first train is 5.3 mph faster, we add that to the second trains value and get our answer. The first train is going at 361.7, the second at 355.7