<em>Hey</em><em>!</em><em>!</em><em>!</em>
<em>here</em><em>'s</em><em> </em><em>your</em><em> </em><em>answer</em>
<em>X+</em><em>1</em><em>2</em><em>8</em><em>=</em><em>1</em><em>8</em><em>0</em><em>(</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>angle</em><em> </em><em>in</em><em> </em><em>straight</em><em> </em><em>line</em><em>)</em>
<em>or</em><em>,</em><em>X=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>1</em><em>2</em><em>8</em>
<em>X=</em><em>5</em><em>2</em><em> </em><em>degree</em><em>.</em>
<em>So</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>X </em><em>is</em><em> </em><em>5</em><em>2</em><em> </em><em>degree</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
Answer:
obtain from (a number) another which contains the first number a specified number of times.
Answer:
D. zero
Step-by-step explanation:
Since the graphs do not intersect, there are zero solutions.
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function 
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
For starters, create an equation to show David's earnings. We can do this using Danielle's as a basis, which is set up as y=(# of hours)x+(bonus). This gives us y=12x+80. Now, as we need both their ys to be equal, we just set both equations equal to each other, making 15x+50=12x+80. Now, we solve for x, starting with 15x+50=12x+80, subtracting 12x from both sides to get 3x+50=80, subtracting 50 from both sides to get 3x=30, and dividing three from both sides to get x=10. To check, we just plug in our answer to both equations and see if the ys match up. With Danielle's equation, we get y=15(10)+50=150+50=200 and with David's equation, we get y=12(10)+80=120+80=200, proving that our answer is correct.
