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Usimov [2.4K]
2 years ago
7

1/2(4y+6)=4-2(y-6)/3​

Mathematics
1 answer:
ANEK [815]2 years ago
7 0

Answer:

-2

Step-by-step explanation:

hope it helps please mark me as brainliest

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Which of the following statements are equivalent to the statement "Not all cats do not like having their belly rubbed"?
notka56 [123]

Answer:

“Not all cats dislike having their belly rubbed”

Step-by-step explanation:

Just try not to repeat words because it is confusing and wordy.

6 0
3 years ago
Simplify.
ValentinkaMS [17]


first, you would rearrange the equation so that like terms were next to each other.

7y - 5y - x2 + 2x2 +3x - 17x

then you would reduce the equation based on like terms

2y + x2 - 14x

then simply rearrange the equation to get the answer, which is <u>B</u>

5 0
3 years ago
Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a
Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = \frac{1}{6}

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

E(X)=\sum x\cdot P(X=x)

Compute the expected monetary value of a single roll as follows:

E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17

Thus, the expected monetary value of a single roll is $1.17.

7 0
3 years ago
. Scalene triangle SCL with angle bisector CM
Firdavs [7]
32 but make sure it’s emedicpend PAS
3 0
3 years ago
PLEASE HELP
Elenna [48]
C-400 is the answer !!
6 0
2 years ago
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