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Usimov [2.4K]
3 years ago
7

1/2(4y+6)=4-2(y-6)/3​

Mathematics
1 answer:
ANEK [815]3 years ago
7 0

Answer:

-2

Step-by-step explanation:

hope it helps please mark me as brainliest

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The volume of the cylinder is V=1/3r^2h, where r is the radius and h is the height. if the radius of a cylinder is 3 inches and
Makovka662 [10]

Answer:

75 inches

Step-by-step explanation:

with this we use change of subject

V=1/3

Pie=3.14

radius =3

height =8

so therefore

V=1/3 ×3.14×3×3×8

V=75.36

8 0
3 years ago
2. Which of the following is a common factor of *<br> 4x? - 12x² and 8x² - 4x?
Orlov [11]

Answer:

Im not sure but hiiiiiiiiii.

Step-by-step explanation:

4 0
3 years ago
Classify each function as even, odd, or neither even nor odd.
drek231 [11]

The function

f(x) is even

g(x) is neither even nor odd

h(x) is odd

Steps:

for an even function it holds that f(-x) = f(x):

f(-x) = (-1)^6 x^6  - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even

for an odd h(x) it holds that h(-x) = -h(x):

h(-x) = (-1)^5x^5-(-1)^3x^3 = -(x^5-x^3) = -h(x) \implies h(x)\,\, \mbox{even}

It is easy to show that g(x) does not match any of the two possibilities above.


8 0
3 years ago
Read 2 more answers
Question: <br> Write the ratio as a fraction in the simplest form.<br><br> Solve: 2 1/3 : 4 1/2
VARVARA [1.3K]
The answer is 14/41
3 0
3 years ago
Statistics Probability
andriy [413]

Answer:

Explained below.

Step-by-step explanation:

Denote the variable as follows:

M = male student

F = female student

Y = ate breakfast

N = did not ate breakfast

(a)

Compute the probability that a randomly selected student ate breakfast as follows:

P(Y)=\frac{n(Y)}{N}\\\\=\frac{198}{330}\\\\=0.60

(b)

Compute the probability that a randomly selected student is female and ate breakfast as follows:

P(F\cap Y)=\frac{n(F\cap Y)}{N}\\\\=\frac{121}{330}\\\\=0.367

(c)

Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:

P(M|Y)=\frac{n(M\cap Y)}{n(Y)}\\\\=\frac{77}{198}\\\\=0.389

(d)

Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:

P(Y|M)=\frac{n(Y\cap M)}{n(M)}\\\\=\frac{77}{154}\\\\=0.50

(e)

Compute probability of the student selected "is male" or "did not eat breakfast" as follows:

P(M\cup N)=P(M)+P(N)-P(M\cap N)\\\\=\frac{n(M)}{N}+\frac{n(N)}{N}-\frac{n(M\cap N)}{N}\\\\=\frac{n(M)-n(N)-n(M\cap N)}{N}\\\\=\frac{154+132-77}{330}\\\\=0.633

(f)

Compute the probability of "is male and did not eat breakfast as follows:

P(M\cap N)=\frac{n(M\cap N)}{N}\\\\=\frac{77}{330}\\\\=0.233

4 0
3 years ago
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