All categories

3 years ago

The Nisbets went through the drive through

Mathematics

1 answer:

Alexandra [31]3 years ago

8 0

Answer:

One cup of coffee is $3.25

Step-by-step explanation:

Create a system of equations where c is the cost of a cup of coffee and d is the cost of a donut

2c + 4d = 10.5

c + 5d = 8.25

Solve by elimination by multiplying the top equation by -5 and the bottom equation by 4

-10c - 20d = -52.5

4c + 20d = 33

Add them together and solve for c

-6c = -19.5

c = 3.25

So, a cup of coffee is $3.25

You might be interested in

Fern rounded to the nearest ten to estimate 548-132. She subtracted 540-130 and got 410. Is Fern's estimate correct? Explain.

tensa zangetsu [6.8K]

Fern's estimate is not correct because he rounded 548 wrong, it would be rounded to 550 instead since the number 8 is closer to 10. So the correct answer would be 420.

6 0

3 years ago

Please please Help me!!!!!

pav-90 [236]

Answer:

19,23

Step-by-step explanation:

9+x-7≥ 21

Combine like terms

2+x≥21

Subtract 2 from each side

2+x-2 ≥21-2

x≥19

Any number greater than or equal to 19

3 0

3 years ago

Which of the following statements is logically equivalent to "If I study, then I get better grades"? If I do not study, then I d

saul85 [17]

It would go along with, "if I get better grades, then I study."

3 0

3 years ago

Read 2 more answers

Tonya’s dog-walking service charges a flat rate of $20 per month, plus $3 per mile that each dog is walked. Beth does not charge

vladimir1956 [14]

Answer:

Ten miles

Step-by-step explanation:

Use this inequality

20 + 3m = 5m

4 0

2 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago