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Anastasy [175]
3 years ago
10

27 solid iron spheres, each of radius 'xcm'ate melted to form a sphere with radius 'ycm',find the ratio x:y​

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:3:1

Step-by-step explanation:

Given

There are 27 solid spheres of  radius x cm

The volume of a sphere is \frac{4}{3}\pi r^3

The volume of 27 old spheres is the same as the volume of a new sphere

The volume of the old spheres is

V_o=\dfrac{4}{3}\pi x^3

The volume of a new sphere is

V_n=\dfrac{4}{3}\pi y^3

Now,V_o=V_n

\Rightarrow 27\times \dfrac{4}{3}\pi x^3=\dfrac{4}{3}\pi y^3\\\\\Rightarrow (\dfrac{x}{y})^3=27\\\\\Rightarrow \dfrac{x}{y}=3

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frez [133]
\text {Laura = }  12 \text { years } 3 \text { months }

\text {Lisa = }  11 \text { years } 7 \text { months }

\text {Deborah = }  11 \dfrac{1}{2}  \text { years } =  11 \text { years } 6 \text { months }

\text {Elizabeth = }  11 \dfrac{1}{3}  \text { years } =  11 \text { years } 4 \text { months }

-----------------------------------------------------
Find Total :
-----------------------------------------------------
\text {Total = } 12 \text { yr } 3 \text { mth } + 11 \text { yr } 7 \text { mth } + 11 \text { yr} 6 \text { mth} +11 \text { yr } 4 \text { mth}

\text {Total = } 45 \text { years } 20 \text { months }

-----------------------------------------------------
Find Average :
-----------------------------------------------------
\text {Average = } (45 \text { years } 20 \text { months }) \div 4

\text {Average = } 560 \text { months } \div 4

\text {Average = } 140 \text { months } \div 4

\text {Average = } 11 \text { years } 8 \text { months }

----------------------------------------------------------------------------------------------------------
\bf \text {Answer : Average = } 11 \text { years } 8 \text { months }
----------------------------------------------------------------------------------------------------------
6 0
3 years ago
Vera has $10$ white socks, $10$ black socks, $10$ brown socks, $10$ blue socks, and $10$ red socks. How many socks (at a minimum
UNO [17]

The minimum number of socks that she needs to get such that a pair is always formed is 5.

<h3></h3><h3>How many socks must she get to be ensured of having a pair?</h3>

We know that she has:

  • 10 white socks.
  • 10 black socks
  • 10 brown socks
  • 10 blue socks.

First, we need to compute the maximum number of socks she needs to take in such a case that no pair is formed.

That will be 4, and represents the case where:

1 white sock, 1 black sock, 1 brown sock, and 1 blue sock are drawn. At that point, no pairs are formed.

Now, if she draws another sock, a pair will always be formed.

From this, we conclude that if she draws 5 socks, always at least one pair will be formed.

If you want to learn more about combinations, you can read:

brainly.com/question/11732255

3 0
2 years ago
Solve 10 and 11 . Show and explain your work.
DaniilM [7]

Answer:

500-75y=x.    And.       44+14y=x.  No work needed

Step-by-step explanation:

6 0
3 years ago
30 POINTS HELP ANSWER ASAP AND EXPLAIN STEP BY STEP HOW TO SOLVE The two non-parallel sides of an isosceles trapezoid are each 7
weeeeeb [17]
See diagram
I wrote that the degrees are 70 each because it is isocolese and 140/2=70


a.
to solve for the diagonal, I'm going to use trig to find the height and the base then use pythagorean theorem to find the diagonal

so
see I've drawn an auxiliry line to make a right triangle on the leftmost side
so
we want to find the height and base
sin(70°)=h/7
so 7sin(70°)=h≈6.57785

cos(70°)=base/7
so 7cos(70°)=base≈2.39414

now
the entire long base is 22, so that big triangle with the diagonal as the hyptonuse is 22-2.39414=19.6059
use pythagorean theorem, like 6.57785²+19.6059²=diagonal²
we get that the diagonal is about 20.68ft




b.
we got that the base was 7cos(70°)
2 of those bases so 22-14cos(70°)=17.2117ft or rounded 17.21ft




a. 20.68ft
b. 17.21ft

3 0
3 years ago
Read 2 more answers
2x&lt;15 solve for x
Nadusha1986 [10]

Answer:

x < 7.5

Step-by-step explanation:

Divide by 2 on both sides to find x

2x/2 < 15/2

x <15/2

x<7.5

4 0
3 years ago
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