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The minimum number of socks that she needs to get such that a pair is always formed is 5.
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How many socks must she get to be ensured of having a pair?</h3>
We know that she has:
- 10 white socks.
- 10 black socks
- 10 brown socks
- 10 blue socks.
First, we need to compute the maximum number of socks she needs to take in such a case that no pair is formed.
That will be 4, and represents the case where:
1 white sock, 1 black sock, 1 brown sock, and 1 blue sock are drawn. At that point, no pairs are formed.
Now, if she draws another sock, a pair will always be formed.
From this, we conclude that if she draws 5 socks, always at least one pair will be formed.
If you want to learn more about combinations, you can read:
brainly.com/question/11732255
Answer:
500-75y=x. And. 44+14y=x. No work needed
Step-by-step explanation:
See diagram
I wrote that the degrees are 70 each because it is isocolese and 140/2=70
a.
to solve for the diagonal, I'm going to use trig to find the height and the base then use pythagorean theorem to find the diagonal
so
see I've drawn an auxiliry line to make a right triangle on the leftmost side
so
we want to find the height and base
sin(70°)=h/7
so 7sin(70°)=h≈6.57785
cos(70°)=base/7
so 7cos(70°)=base≈2.39414
now
the entire long base is 22, so that big triangle with the diagonal as the hyptonuse is 22-2.39414=19.6059
use pythagorean theorem, like 6.57785²+19.6059²=diagonal²
we get that the diagonal is about 20.68ft
b.
we got that the base was 7cos(70°)
2 of those bases so 22-14cos(70°)=17.2117ft or rounded 17.21ft
a. 20.68ft
b. 17.21ft
Answer:
x < 7.5
Step-by-step explanation:
Divide by 2 on both sides to find x
2x/2 < 15/2
x <15/2
x<7.5