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2 years ago

An exponential decay function represents a quantity that has a decreasing halving time true or false

Mathematics

1 answer:

timofeeve [1]2 years ago

4 0

Answer:

In mathematics, exponential decay describes the process of reducing an amount by a consistent percentage rate over a period of time. ... You can compare and contrast the differences between exponential growth and decay, but it's pretty straightforward: one increases the original amount and the other decreases it.

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Eli is moving to a new city. He packs his belongings in cube-shaped boxes that each have a volume of one cubic foot. He places t

klemol [59]

Answer:

jnnm mnn m

Step-by-step explanation:

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3 years ago

Solve (2 - x)^2 < 4/25

Semenov [28]

Answer:

8/5 < x< 12/5

Step-by-step explanation:

(2 - x)^2 < 4/25

Take the square root of each side

sqrt((2 - x)^2) <±sqrt( 4/25)

Make two equations

2-x < 2/5 2-x > -2/5

Subtract 2 from each side

2-x-2 < 2/5 -2 2-x-2 > -2/5-2

-x < 2/5 - 10/5 -x > -2/5 - 10/5

-x < -8/5 -x > -12/5

Multiply by -1, remembering to flip the inequality

x> 8/5 x < 12/5

8/5 < x< 12/5

5 0

3 years ago

Read 2 more answers

A full moon occurs about every 30 days . If the last full moon occurred on a Friday, how many days will pass before a full moon

pentagon [3]

The answer is 30 days until it appears on a Friday again. In order to see the full moon again, we have to go through the entire cycle. So, it will be about 30 days before we would have seen another one.

7 0

3 years ago

The smallest number that has 1, 2, 3, 4, and 5 asfactors.

STALIN [3.7K]

Answer:

The answer is 60

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2 years ago

Define fn : [0,1] --> R by the

sasho [114]

Answer:

The sequence of functions $\{x^{n}\}_{n\in \mathbb{N}}$ converges to the function

$f(x)=\begin{cases}0&0\leq x$ .

Step-by-step explanation:

The limit $\lim_{n\to \infty }c^{n}$ exists and converges to zero whenever $\lvert c \rvert$ . But, if $c=1$ the sequence $\{c^{n}\}$ is constant and all its terms are equal to $1$ , then converges to $1$ . Using this result, consider the sequence of functions $\{f_{n}\}$ defined on the interval $[0,1]$ by $f_{n}(x)=x^{n}$ . Then, for all $0\leq x$ we have that $\lim_{n\to \infty}x^{n}=0$ . Now, if $x=1$ , then $\lim_{n\to \infty }x^{n}=1$ . Therefore, the limit function of the sequence of functions is