Answer:
II. One and only one solution
Step-by-step explanation:
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.
Let assume the equation is given as;
x + 3y = 11 .... 1
x - y = -1 ....2
Using elimination method
Subtract equation 1 from 2
(x-x) + 3y-y = 11-(-1)
0+2y = 11+1
2y = 12
y = 12/2
y = 6
Substitute y = 6 into equation 2:
x-y = -1
x - 6 = -1
x = -1 + 6
x = 5
Hence the solution (x, y) is (5, 6)
<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>
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Answer:
$45
Step-by-step explanation:
30% ÷100 =0.3. 0.3×150= 45
Answer:
Step-by-step explanation:
what grade are you on lemme help you
Answer:
126
Step-by-step explanation:
In order to find the initial number, we need to create the expression that is being mentioned and solve for the initial value by applying the opposite expressions to isolate the variable.
(((x / 42) * 8) + 10) = 34 ... subtract 10 from both sides
((x / 42) * 8) = 24 ... divide both sides by 8
(x / 42) = 3 ... multiply both sides by 42
x = 126
Finally, we can see that the initial value was 126
The distance formula for two points in a plane is
D=sqrt( (x1-x2)^2 + (y1-y2)^2 )
From T to U
D= sqrt((80-20)^2 + (20-60)^2) = 72.11
Then flying from U to V
D= sqrt((20-110)^2 + (60-85)^2) = 93.4
So T to U to V = 72.11+93.4 = 165.5
BUT checking also T to V to U
From T to V
D= sqrt((80-110)^2 + (20-85)^2) = 71.6
Then from V to U
D= sqrt((110-20)^2 + (85-60)^2) = 93.4
So from T to V to U = 165
Pretty much the same both directions
So yes the answer is A
