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2 years ago

How to subtract 4/5 and 3/10 in simplest form

2 answers:

5 0

1- find a common denominator of 5 and 10. Their least common denominator is 10 so convert 4/5 to a fraction with a denominator of 10 ( 8/10). Now subtract 3/10 from 8/10 to get 5/10.

g100num [7]2 years ago

3 0

First you must find a common denominator. In this case 10 will work. You then multiply the top number by whatever you multiplied the bottom number by. This is shown below:
4/5- 3/10 = 8/10- 3/10
You can now solve this to get 5/10. This answer can then be reduced to 1/2.

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Sam has 3 bottles of water. Together, Sam and Dave have at most 12 bottles of water.

finlep [7]

If you need to find out how many bottles of water Dave has then at the most it would be 9 bottles

7 0

3 years ago

Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the

ludmilkaskok [199]

By Stokes' theorem,

$\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$

where $\mathcal C$ is the circular boundary of the hemisphere $\mathcal M$ in the $y$ - $z$ plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

$\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle$

where $0\le t\le2\pi$ . Then the line integral is

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt$
$=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi$

We can check this result by evaluating the equivalent surface integral. We have

$\nabla\times\mathbf f=\langle1,0,0\rangle$

and we can parameterize $\mathcal M$ by

$\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle$

so that

$\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv$

where $0\le v\le\dfrac\pi2$ and $0\le u\le2\pi$ . Then,

$\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi$

as expected.

7 0

3 years ago

I need help or the answer

loris [4]

Answer:

5x+4y = 52

Step-by-step explanation:

We can first write the equation in point slope form

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y - 8 = -5/4 ( x-4)

Multiply each side by 4 to get rid of the fraction

4(y - 8) = 4*(-5/4) ( x-4)

4(y - 8) = -5 ( x-4)

Distribute

4y - 32 = -5x+20

We want the equation in the form

Ax + By = C

Add 5x to each side

5x+4y -32 = -5x+5x+20

Add 32 to each side

5x+4y -32+32 =32+20

5x+4y = 52

4 0

3 years ago

The circle has an area of 144 <br><br> What is the radius and diameter

vichka [17]

Answer:

for the radius, the cloest i could get was 6.77. therefore the diametre would be double meaning its would be 13.54

so sorry if this is incorrect!

8 0

2 years ago

Read 2 more answers

Blaire needs more than 616 total points on assignments in her math class to pass. She only has 224 points and needs to do some e

jek_recluse [69]

Answer: The answer is x >7

Step-by-step explanation:

56⋅x>616−224

56⋅x>616-224

Simplify :

56⋅x>392

Dividing by the variable coefficient :

392

x>39256

Simplify :

x>7

Inequality

56⋅x+224>616

is true for

x>7

4 0

3 years ago