All categories

2 years ago

Find the matrix product, if possible.

Mathematics

1 answer:

kondor19780726 [428]2 years ago

3 0

Answer:

below.

Step-by-step explanation:

The number of columns in the first matrix must equal to the number of rows in the second for multiplication to be possible.

Here first matrix has 3 columns and second one has 3 rows so POSSIBLE.

[ -8 2 2] { 3 }

[ 0 ]

[ -3]

= -8*3 + 2*0 + 2 * -3 = [-30] <-------- Answer.

Note a 1*3 matrix multiplied by a 1*3 matrix gives a 1*1 result.

You might be interested in

You scored 85% on your math quiz. The quiz was out of 50 points. How many points did you get?

malfutka [58]

Answer:

Step-by-step explanation:

4 0

2 years ago

WORTH 100 POINTS!!!!!

aleksklad [387]

Answer:

1. This graph is not a function, because for every y there are more than one x.

2. This graph is not linear because it is not a straight line.

3. It took them 6 hours to get to their destination.

4. The destination was 325 miles away.

5. They might have stopped at a restaurant to eat.

6 0

2 years ago

Read 2 more answers

Write the conversion factor for seconds to minutes. Use the factor to convert 135 seconds to minutes.

OverLord2011 [107]

Answer

Find out the conversion factor for seconds to minutes and convert 135 seconds to minutes.

To prove

1 minute = 60 second

for seconds to minutes.

$1 second = \frac{1}{60}\ minutes$

Therefore the conversion factor for seconds to minutes be

$= \frac{1}{60}\ minutes$

Now convert 135 seconds to minutes.

$= \frac{135\times 1}{60}$

= 2.25 minutes

Hence proved

4 0

3 years ago

Read 2 more answers

A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u

OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

$\displaystyle\frac{8000\pi\sqrt{2}}{3}$

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

$x^2+y^2=15^2\to y=\sqrt{225-x^2}$

Then we set the integral for the volume by using shell method:

$\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx$

That can be solved by substitution:

$u=225-x^2\to du=-2xdx$

The limits of integration also change:

For x=5: $u=225-5^2=200$

For x=15: $u=225-15^2=0$

So the integral becomes:

$\displaystyle -\int_{200}^{0}\pi \sqrt{u}du$

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

$\displaystyle \int_{0}^{200}\pi u^{1/2}du$

Then applying the basic rule we get:

$\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}$

Since that is just half of the solid, we multiply by 2 to get the complete volume:

$\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}$

$=\displaystyle\frac{8000\pi\sqrt{2}}{3}$

5 0

3 years ago

Please help! I really need help!

Musya8 [376]

Answer:104 degrees

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers