I need help to see if their equivalent help fast pls
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The value of expanding (2x -3)^4 is 16x^4 + 96x^3 +216x^2 -216x + 81
<h3>How to expand the expression?</h3>The expression is given as:
(2x -3)^4
Using the binomial expansion, we have:
Evaluate the combination factors.
So, we have:
Evaluate the exponents and the products
Hence, the value of expanding (2x -3)^4 is 16x^4 + 96x^3 +216x^2 -216x + 81
Read more about binomial expansions at:
#SPJ1
Ok first we can split it in two : 
and 
.
The derivative of is 3.
For the first part, we use the chain rule :![[f(g(x))]'=g'(x)f'(g(x))](https://tex.z-dn.net/?f=%5Bf%28g%28x%29%29%5D%27%3Dg%27%28x%29f%27%28g%28x%29%29)
hence 
(since the derivative of the exponential is itself) hence 
The derivative of
For the first part, we use the chain rule :