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Scenario: The Cannon Instructions: View the video found on page 1 of this Journal activity. Using the information provided in th

Artyom0805 [142]

Answer:

Part A

Yes

Part B

He will land at a point 30 meters from Cannon

Step-by-step explanation:

Part A

The given function that represent the path of the Cannon, which is the path of a parabolic arc, is presented as follows;

f(x) = -0.05·(x² - 26·x - 120)

We note that the height, 'h', of the path of a parabola at a horizontal distance, 'x' from the origin is equal to f(x)

Therefore, given that at the ground level, at the start and end of the flight, the f(x) = 0, we can write;

-0.05·(x² - 26·x - 120) = 0

∴ x² - 26·x - 120 = 0

x = (26 ± √((-26)² - 4 × 1 × (-120)))/(2 × 1)

Which gives;

x = 30 or x = -4

Therefore, he lands at a point 30 meters from the starting point

Therefore, the function gives enough information to tell where he will land

Part B

He lands at the point, x = 30 from the point the cannon was fired.

3 0

2 years ago

3. Six less than twice a number is 17. Which equation could be used to determine the

Usimov [2.4K]

Answer & Step-by-step explanation:

n represents our number. So, twice a number would be 2n because twice means multiply by two.

When the problem says 6 less, then it means 6 less than 2n. So, it would look like 2n-6.

FInally, the problem says that all of this equals 17 so 17 would be the result.

So, you answer is 2n-6 = 17. This is answer choice B.

6 0

3 years ago

PLEASE HELP I WILL BRAINLIEST, MY GPA RELIES ON THIS!! IM BEGGING HERE

MAVERICK [17]

Step-by-step explanation:

it's so much work, here's the first half untill i do the rest

i added the rest, i hope i helped somehow good luck!! :)

5 0

3 years ago

The circle graph shows how a family spends its annual income. If $26,450 is used for Auto and Entertainment combined, what is th

nika2105 [10]

12%+11%=23% so, $26,450/.23=$115,000.

5 0

3 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

b.

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

c.

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

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