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inn [45]
3 years ago
5

Someone please explain step by step.

Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0

Answer:

{10}^{th}  \: term  =  \frac{5}{512}

Step-by-step explanation:

geometric progression formula:

{n}^{th} \:  term  = ar ^{n - 1}

given:

common ratio, r = 1/2

first \: term \:  = 5

1) find the value of a

{n}^{th}  \: term \:  = a {r}^{n - 1}

we're finding the 1st term, so substitute 1 into n:

{1}^{st}  \: term  = a( \frac{1}{2} ) {}^{1 - 1}

first term is 5. so we substitute 5 into the equation:

5 = a(1)

a = 5

2) find the 10th term

we're finding the 10th term, so substitute 10 into the equation and don't forget to substitute 5 into a:

{10}^{th}  \: term  = 5( \frac{1}{2} ) {}^{10 - 1}

{10}^{th}  \: term  = 5( \frac{1}{512} )

{10}^{th}  \: term =  \frac{5}{512}

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<u>Story Problem</u>

Mr. Bill Gates bought a house in Italy for \$506,211 and a house in Canada for \$424,809. What is the total cost of the two houses?

we know that

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so

\$506,211+\$424,809=\$931,020

therefore

the answer is

The total cost is \$931,020

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I can't figure this question out I've tried multiple times but only 2/3. Help, please.
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Step-by-step explanation:

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There are 24 students in a class. 8 of the students are boys. Write th amount of the boys in the class as a fraction in its simp
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Find the equation of the line of the circle passing through the points (1,2) (3,-4) (5,-6)
Cerrena [4.2K]

Answer:

(x-11)² + (y-2)² = 10²

Step-by-step explanation:

Given circle passes through

P(1,2), Q(3,-4), R(5,-6)

Assume following circle with centre O(a,b) and radius r contains P,Q,R.

(x-a)²+(y-b)² = r^2 ...........(1)

Substitute P in (1) and expand, simplify

(1-a)²+(2-b)²=r²

a²+b² -2a-4b+5-r²=0  .......(2)

Similarly, substitute Q in (1) and expand, simplify

(3-a)²+(-4-b)² = r²

a²+b²-6a+8b+25-r²=0  ...........(3)

Similarly, substitute R in (1) and expand, simplify

(5-a)²+(-6-b)² = r²

a²+b²-10a+12b+61-r²=0  ...........(4)

We can now eliminate a^2 and b^2 by simple subtractions

(2) - (3)

4a-12b-20 = 0   ..........(5)

(3) - (4)

4a-4b-36 = 0   .............(6)

Finally, (6) - (5) and solve for b

8b - 16 = 0

b=2   ..............................(7)

substitute b in (5) and solve for a

4a-12(2) -20 =0

4a=44

a=11  ................................(8)

Finally, substitute a & b in (2) to solve for r

r^2 = 11²+2²-2*11-4*2+5 = 121+4-22-8+5 = 100

r=sqrt(100) = 10  (positive value only)

therefore the equation of the circle is

(x-11)² + (y-2)² = 10²

6 0
3 years ago
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