We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
Answer:
BẠN BỊ ĐIÊN À
Step-by-step explanation:
CÚT
= 2025
When you are told to find the smallest length possible, you perform L.C.M(Least common multiples)
For this, you divide the given lengths using the numbers that divides all through.
I have added an image to this answer. Go through it for more explanation
Answer:
squares
Step-by-step explanation:
Move everything to one side
Equation
2x^2 - 5x -3 = 0
Sq rt means square root or radical sign
Quadratic equation-> x = - (b) +/- Sq rt b^2 -4ac
2a
- (-5) +/- Sq rt (-5)^2 - 4(2)(-3)
2 (2)
5 +/- Sq rt 25 + 24
4
Sq rt 29 = 5.38
5 + Sq rt 29 divides over 4 and 5 - Sq rt 29 divides over 4.
