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Svetach [21]
3 years ago
5

Line segements AB and CB intersect outside of the circle P as shown. What is the value of x? A.11/4 B.8 C.2 D. 9/2

Mathematics
1 answer:
Aleks [24]3 years ago
7 0
They answer is A because when you solve it it will give you A
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How many ounces are in 2 ounces
VARVARA [1.3K]

Answer:

2 ounces are in 2 ounces

Step-by-step explanation:

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4 years ago
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You get GPS units from two manufacturers, A and B. You get 43% of your units from A and 57% of your units from B. In the past, 2
defon

Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715

Probability a unit is defective and from manufacturer A:

2% of 43%. So

P(A \cap B) = 0.02*0.43 = 0.0086

What is the probability that it came from manufacturer A?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015

0.5015 = 50.15% probability that it came from manufacturer A.

4 0
3 years ago
Set up an equation and solve the following problem.
nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

<u>Again</u>

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

<u>For Dave</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, t = \dfrac{\textrm d miles}{\textrm s miph}

Or, t = \dfrac{\textrm 210 miles}{\textrm s miph}

<u>For Kent</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, T = \dfrac{\textrm D miles}{\textrm S miph}

Or, T = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

∵ Time taken by both is same

So, t = T

Or,  \dfrac{\textrm 210 miles}{\textrm s miph} = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴  s = \dfrac{840}{20}

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0
3 years ago
13.989 to the nearest 10th
Paladinen [302]
13.989 to the nearest 10th is 14
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3 years ago
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Please help with these three questions! Thank you! (No links! No trolls! Will mark brainliest!)
gtnhenbr [62]

Answer:

1. 4*10^7

2. 5.1*10^-7

3.9,842,000,000(9.842*10^9)

7 0
2 years ago
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