All categories

3 years ago

Please help asap question four

Mathematics

1 answer:

son4ous [18]3 years ago

4 0

Answer:

5p + 2

Step-by-step explanation:

You might be interested in

NEEED TO BE DONE ASAP!!!PLease

strojnjashka [21]

Answer:

14: 56= 1:4, dividing both sides by 14

Online sale: shop sales = 180: 240 = 3: 4, dividing both sides by 60.

3 0

3 years ago

Giải phương trình y"= lnx

kipiarov [429]

Integrate both sides with respect to x :

$y''(x) = \ln(x) \implies \displaystyle \int y''(x)\,\mathrm dx = \int \ln(x)\,\mathrm dx$

On the right side, integrate by parts with

$f = \ln(x) \implies \mathrm df = \dfrac{\mathrm dx}x \\\\ \mathrm dg = \mathrm dx \implies g = x$

$\implies \displaystyle \int\ln(x)\,\mathrm dx = fg - \int g\,\mathrm df \\\\ \int\ln(x)\,\mathrm dx= x\ln(x) - \int \mathrm dx \\\\ \int\ln(x)\,\mathrm dx= x\ln(x) - x + C_1$

Then

$\displaystyle y'(x) = x\ln(x) - x + C_1$

Integrate both sides with respect to x by parts again, this time with

$f = \ln(x) \implies \mathrm df = \dfrac{\mathrm dx}x \\\\ \mathrm dg = x\,\mathrm dx \implies g = \dfrac{x^2}2$

$\implies \displaystyle \int x\ln(x)\,\mathrm dx = fg-\int g\,\mathrm df \\\\ \int x\ln(x)\,\mathrm dx = \dfrac{x^2\ln(x)}2 - \int\frac x2\,\mathrm dx \\\\ \int x\ln(x)\,\mathrm dx = \dfrac{x^2\ln(x)}2-\dfrac{x^2}4 + C_2$

Then

$y(x) = \dfrac{x^2\ln(x)}2 - \dfrac{x^2}4 - \dfrac{x^2}2 + C_1x + C_2 \\\\ \boxed{y(x) = \dfrac{(2\ln(x)-3)x^2}4 + C_1x + C_2}$

3 0

3 years ago

1. If 8 is 40% of a value, what is the value?

liubo4ka [24]

Answer:

20 is the answer.

5 0

3 years ago

Read 2 more answers

3. Solve each equality or inequality: a. |8x-6|= 0

larisa [96]

Answer:

x = 3/4

Step-by-step explanation:

Step 1: Find possibilities.

We know one possibility: 8x - 6 = 0. This is because 0 cannot be positive or negative.

Step 2: Solve possibility 1.

$8x - 6 = 0$
$8x - 6 + 6 = 0 + 6$ (Add 6 to both sides)
$8x = 6$
$\frac{8x}{8} =\frac{6}{8}$ (Divide both sides by 8)
$x = \frac{3}{4}$

Therefore, x = 3/4.

6 0

3 years ago

Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. What is the estimat

a_sh-v [17]

Step-by-step explanation:

Given that Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. We are to calculate the probability that Rita will need to pick atleast 5 beads before she picks a grey bead from her collection.

Prob for drawing atleast 5 beads before she picks a grey bead from her collection

= 1-Prob for drawing atleast one grey beed in the first 5 draws.

(Because these two are complementary events)

no of grey beeds drawn in first 5 trials is

Bi=(5,1/6)

Prob for drawing atleast one grey beed in the first 5 draws.

=1-Prob of no grey

Hence required prob=P(X=0 in first 5 draws)

= 0.4018

6th beeds onwards can be grey also.

Nearest answer is c)0.45

7 0

3 years ago