Twelve people join hands for a circle dance.In how many ways can they do this? Suppose six of these people are men, and the other six are women. In how many ways can they join hands for a circle dance, assuming they alternate in gender around the circle
Answer:
86400 ways
Step-by-step explanation:
Since the circle can be rotated, the number of ways to arrange a distinct number of n objects in a circle will be (n−1)!.
Now, if we rotate the circle with the six women, we will see that there are 5! ways with which they can be placed in the circle.
After picking the places for the women, we will now fill each gap between two women with a man.
We have 6 men. Thus, number of ways to arrange the men is 6!
Thus,number of ways they can join hands for a circle dance, assuming they alternate in gender around the circle = 5! × 6! = 86400 ways
<span>The square root of 944.578756 is </span>30.734
I hope this helps!
- Z
The answer would be B. I think...but I'm not sure. Hope this helps!
Answer:
Step-by-step explanation:
Given
Required
Determine the equivalent expression
Simplify the first fraction
Apply law of indices on the first fraction;
Apply law of indices:
Evaluate the bracket
Collect Like Terms
Hence:
Answer:
AC = 127,26 f distance from home plate to second base
Step-by-step explanation:
Let call A , B , C Home plate, first base and second base respectively
These three point form a right triangle with legs ( AB = BC = 90 feet)
we have an isosceles triangle with a right angle and two angles of 45⁰
So we need to compute distance AC (hypotenuse)
AC² = AB² + BC² ⇒ AC² = 2AB² ⇒ AC = AB √2
AC = 90 * 1,414
AC = 127,26 f
