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ZanzabumX [31]
3 years ago
6

Given that the population proportion is 0.82, the Normal distribution will provide a good approximation to the true sampling dis

tribution of the sample proportion as long as:________.
A) n> 13.
B) n> 30.
C) n> 56.
D) n > 100.
Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Answer:

Then solution as long as n ≥ 56

Step-by-step explanation:

The Normal distribution will provide a good approximation to evaluate proportion tests when the following conditions are met:

n*p₀ > 10

n*q₀ > 10

As  p₀ = 0,82      q₀ = 0,18       n  = 13      30     56    and  100

We test:

A) n = 13        n*q₀  =  13*0,18 = 2,34       2,34 < 10  

B) n = 30       n*q₀  =  30*0,18 = 5,4         5,4 < 10

C) n = 56       n*q₀  =  56 * 0,18 = 10,08

                      n*p₀  = 56 * 0,82 = 45,92

D) n = 100      n*q₀  = 18

                      n*p₀  = 82

If we test 55  we find that  55*0,18  =  9,9

Then solution as long as n ≥ 56

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This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


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