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Phoenix [80]
3 years ago
12

Stimulus check summary please help me please

Mathematics
2 answers:
OleMash [197]3 years ago
8 0

Answer: I think it’s great but you should make a stronger opinion and always have back up evidence

Step-by-step explanation:

Luden [163]3 years ago
5 0
Stimulus checks are checks sent by the U.S. government to taxpayers to boost their spending power and spur economic activity. Stimulus checks are either mailed to taxpayers or an equivalent tax credit is applied to their tax filing.
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T = WP [ M² - ( M-S)² ]​
QveST [7]

Answer:

W PM^2 − WP(M−S)^2=T

Step-by-step explanation:

this is what mathaway said

8 0
3 years ago
Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expect
Alisiya [41]
<span>It's easy enough. Solving looks like that: p(roll of 8)+p(roll of 12) =</span>\frac{5}{36} + \frac{1}{36} = \frac{1}{6} ; \frac{1}{6} *9 +\frac{5}{6}*2 = \frac{3}{2} - \frac{5}{3} = -\frac{1}{6} Hope everything is clear.
5 0
3 years ago
Read 2 more answers
PLEASE HELP FIRST GETS BRAINLIEST
asambeis [7]
I believe that this would be representative.
3 0
3 years ago
Read 2 more answers
What do I do to get the answer and explain step by step!
abruzzese [7]

Answer:24

Step-by-step explanation: 1/6 multaplication. if you multiply 1/6 1 at a time, it increases 1/6 by 1/6 more. If we do this 24 times, we get 4. i know its complicated, but i tried explaining it in my own way. Hope it helps!

7 0
2 years ago
The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =
pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

so that

v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du

\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is s(0)=0\,\mathrm m. Then its displacement over the time interval [0, 3] is

s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}

c) The total distance traveled is the integral of the absolute value of the velocity function:

s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt

v(t) for 0\le t and v(t)\ge0 for \cos^{-1}\left(-\frac29\right)\le t\le3, so we split the integral into two as

\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt

=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt

\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}

4 0
3 years ago
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