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MA_775_DIABLO [31]
3 years ago
11

Quick prints makes custom t-shirts. They charge $10 for each t-shirt ordered plus a $5 design fee. Which situation best represen

ts y, the total cost to order x t-shirts?
Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0

Answer:

y = 10x+5

Step-by-step explanation:

The price of each T-shirt = $10

Design fee on each T-shirt = $5

We need to find the expression for the total cost. Let the total cost be y. So,

Let he has ordered x T-shirts. So,

y = 10x+5

Hence, this is the required solution.

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klasskru [66]

The graph of the quadratic function f(x)=x² - 5x + 12 is a parabola which opens up.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The standard form of a quadratic equation is:

y = ax² + bx + c

The graph of a quadratic equation is a parabola.

The graph of the quadratic function f(x)=x² - 5x + 12 is a parabola which opens up.

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4 0
2 years ago
Please help, been stuck on this question for a while
vichka [17]

Answer:

csc (- Ф) = -29/20

Step-by-step explanation:

We know that:

csc Ф = 1/ sinФ ................. equation 1

csc (- Ф) = - csc Ф .............equation 2

Given that:

sin Ф = 20/29

Using equation 1:

csc Ф = 1/ (20/29)

csc Ф = 29/20

using equation 2:

csc (-Ф) = - csc Ф = -29/20

I hope it will help you!

3 0
3 years ago
Read 2 more answers
324.5 as scientific notation;<br><br> step by step explanation please
dlinn [17]

Answer:

3.456 x 10^11

Step-by-step explanation:

= 3.456 × 10¹¹

scientific notation

= 3.456e¹¹

scientific e notation

= 345.6 × 109

engineering notation

billion; prefix giga- (G)

= 3.456 × 10¹¹

standard form

= 345600000000

(real number)

7 0
3 years ago
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A common inhabitant of human intestines is the bacterium Escherichia coli, named after the German pediatrician Theodor Escherich
Bess [88]

Answer:

a). k = 2.0794

b). A_{t}=A_{0}(2^{3t} )

c). 13107200 cells

d). rate of growth after 6 hours = 27255112

e). 4.76 hours

Step-by-step explanation:

From the formula of bacterial population,

A_{t}=A_{0}e^{kt}

Where A_{t} = Bacterial population after time t

A_{0} = Initial population

k = relative growth factor

t = duration or time

a). For A_{t}=2\times 50=100 cells

and A_{0}=50 cells

Time t = 20 minutes = \frac{1}{3} hours

Now we plug in these values in the formula,

100 = 50(e^{\frac{k}{3}})

e^{\frac{k}{3}}=2

By taking natural log on both the sides of the equation,

\frac{k}{3}(lne)=ln(2)

k = 3ln(2) = 2.0794

b). To get the expression we will plug in the value of k in the formula.

A_{t}=A_{0}e^{kt}

Since k = 3ln(2)

A_{t}=A_{0}e^{3t(ln2)}

Let y = e^{3t(ln2)}

By taking natural log on both the sides of the equation,

lny = ln(e^{3t(ln2)} )

lny = 3t(ln2)ln(e)

ln(y) = 3t(ln2)

ln(y) = ln(2)^{3t}

y = 2^{3t}

Now our expression will be A_{t}=A_{0}(2^{3t} )

c). Number of cells after t = 6 hours

A_{6}=50(2^{3\times 6} )

A_{6}=50(2^{18})

A_{6}=50\times (262144)=13107200

d). We can get the rate of growth by finding derivative of the expression

\frac{d}{dt}(A_{t})=\frac{d}{dt}[A_{0}(e^{kt}})]

          = A_{0}[ke^{kt}]

Now \frac{d}{dt}(A_{6})=k.A_{6}

                   = 2.0794×13107200

                   = 27255112

e) From the given formula,

A_{t}=A_{0}(2^{3t} )

1000000=50(2^{3t} )

2^{3t}=20000

3t(ln2) = ln(20000)

t = \frac{ln(20000)}{3(ln2)}

t = \frac{9.90349}{2.07944}=4.76 hours

3 0
3 years ago
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taurus [48]
((6*2)+y)+(x+15)
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