This graph represents Andre's distance from his bicycle

KIM [24]

8 is to 64 as 2 is to 16

x=16

5 0

2 years ago

Alexis and tara both mine salt. alexis mines 300 pounds in 20 hours. tara mines 400 pounds in 40 hours. which of the following i

Archy [21]

Well, if both Alexis and Tara mine salt for 40 hours... they'd have mine 1,000 pounds of salt. Is this what you were looking for?

7 0

2 years ago

WILL GIVE BRAINLIEST

soldier1979 [14.2K]

Answer:

Range=65

Step-by-step explanation:

The highest is 66 the lowest is 1 so 66-1=65

8 0

2 years ago

About 250,000 people of a certain community live in the country. Of that number, 73,920 live in state A and state B. The number

Elodia [21]

Answer:

15 360 people in State A and 58 560 in State B

Step-by-step explanation:

We have two conditions:

(1) A + B = 73 920

(2) B = 3A + 12 480

Solve the system of equations. Substitute (2) into (1).

A + 3A + 12 480 = 73 920 Subtract 12 480 from each side

4A = 61 440

(3) A = 15 360 Substitute (3) into (2)

B = 3×15 360 + 12 480

= 46 080 + 12 480

= 58 560

There are 15 360 people in State A and 58 560 in State B.

<em>Check: </em>

(1) 15 360 + 58 560 = 73 920 (2) 58 560 = 3×15 360 + 12 480

73 920 = 73 920 58 560 = 46 080 + 12 480

58 560 = 58 560

6 0

2 years ago

The number of rookie cards in a variety pack of baseball cards is normally distributed with a mean of 3 cards and the standard d

Sergio039 [100]

Answer:

$z = \frac{2-3}{\frac{1}{\sqrt{10}}}=-3.163$

$z = \frac{4-3}{\frac{1}{\sqrt{10}}}=3.163$

$P(-3.163$

So then we will expect 9.98 packages between 2-4 rookie cards in the sample of 10

Step-by-step explanation:

Let X the random variable that represent the number of rookie cards of a population, and for this case we know the distribution for X is given by:

$X \sim N(3,1)$

Where $\mu=3$ and $\sigma=1$

We select a sample size of n = 10 variety packs and we want to find this probability:

$P(2$

We can use the z score formula given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

We can find the z score for 2 and 4 and we got:

$z = \frac{2-3}{\frac{1}{\sqrt{10}}}=-3.163$

$z = \frac{4-3}{\frac{1}{\sqrt{10}}}=3.163$

So we can find the probability with this difference

$P(-3.163$

And using the normal standard distirbution or excel we got:

$P(-3.163$

So then we will expect 9.98 packages between 2-4 rookie cards in the sample of 10

4 0

2 years ago