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svp [43]
1 year ago
14

Giving the figure below, what is the measure of angle JKL

Mathematics
1 answer:
Lubov Fominskaja [6]1 year ago
6 0

The measure of < JKL = 25+25 = 50 degrees.

Angle JOK = 360 -230 = 130 degrees , (where O is the center of the circle)

< OLK = < OJK = 90 degrees ( tangent to a circle)

< LOK = < JOK = 180 - (90+65) = 180 - 155 = 25 degrees

The solution is: < JKL = 25 +25 = 50 degrees

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Answer = 1/9 ……………….
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{−2x+7y=−7 <br> −5x+14y=−7
Sati [7]

Answer: x=7, y=2

Step-by-step explanation:

1. -2(-2x+7y=-7) -> 4x-14y=14

2. 4x-14y=14

   -5x+14y=-7

3. -x = 7, x=7

4. -5(7)+14y=-7

5. -35+14y=-7

6. 14y=28, y=2

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3 years ago
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Please help no links!
slavikrds [6]

Answer:

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Step-by-step explanation:

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2 years ago
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Please help I need the answer by 23rd (5 points)​.
IrinaK [193]

Answer:

The relationship between the lengths of the sides of the triangle is that they all follow the Pythagorean Theorem (at least I'm pretty sure that's the answer.

Step-by-step explanation:

If you plug in the smaller sides like 9^2+40^2 which equals to 1681. Then you square 1681, you'll get 41 as your hypotenuse. The sides of triangle provided above your question, should follow the formula given to you which is c^2=a^2+b^2. Just to be safe, you can check if all of the triangle sides actually are true for the Pythagorean theorem.

3 0
3 years ago
If the mean of A and B is 20, the mean of B and C is 24 and the mean of A,B and C is 18.What is the mean of A and C?
Zielflug [23.3K]

Answer:

the mean of A and C is 10

Step-by-step explanation:

Given;

mean of A and B = 20

mean of B and C = 24

mean of A, B and C = 18

\frac{A + B}{2} = 20\\\\A+ B = 40 ---- (1)\\\\\frac{B + C}{2} = 24\\\\B+ C = 48----(2)\\\\\frac{A+ B+ C}{3} = 18\\\\A+ B+ C= 54---(3)\\\\From (1); \ A = 40 - B\\\\From(2); \ C = 48 - B\\\\\Substitute \ the \ values \ of \ A \ and \ C \ into \ (3)\\\\(40-B) + B + (48-B) = 54\\\\simplify;\\\\(40 + 48) + (B-B-B)= 54\\\\88 -B = 54\\\\-B = 54-88\\\\-B = -34\\\\B = 34

Recall; A = 40 - B

           A = 40 - 34

           A = 6

Also, C = 48 - B

        C = 48 - 34

       C = 14

Therefore, the mean of A and C is calculated as;

= \frac{A + C}{2} \\\\= \frac{6 + 14}{2} \\\\= 10

5 0
3 years ago
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