The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
Read more about function intervals at:
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Hi there! Lily has $31.50 left.
To find our answer we first need to know the amount of money Lily spend.
Therefore, Lily spend $3.50. Now we subtract this amount of money from the amount she initially owned.
Hence, Lily has $31.50 left.
An unknown variable ..............
Answer:
Since the slope of the line x= - 5 is infinite
The line will be parallel to y axis.
And the line passes through - 2, so the equation will become x= -2
1. sin<span> (30°) = 1/2; 2. </span>sin<span> (300°) = - 3/2; 3. tan (30°) = 3/3; </span>4<span>. </span>sin<span> (45°) = 2/2; 5. sec (</span><span>240°) = -2; </span>6<span>. </span>sin<span> (</span>60<span>°) = 3/2; 7. </span>cos<span> (45°) = 2/2: Start a new line. 8. </span>cos<span> ... 17. tan (</span>150<span>°) = - 3/3; 18. </span>csc<span> (30°) = 2; 19. </span>csc<span> (45°) = 2; 20. </span>sec<span> (</span>210<span>°) = -2 3/3: Start a new line. 21. </span>cot<span> (45°) = 1; 22. sec (45°) = 2; 23. </span>sin<span> (330°) = -1/2; </span>24<span>. tan (135°) = -1 ...</span>
