Answer:
16m and 12m
Step-by-step explanation:
2x + 2(x - 4) = 56
4x = 64
x = 16
Sides are 16 m and 12 m
Question:
If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.
Answer:


Step-by-step explanation:
Given
cos(θ) =-8/17
Required
sin(θ) = __
tan(θ) =__
The first step is to determine the length of the third side
Given that

Where Adj and Hyp represent Adjacent and Hypotenuse

By comparison

Using Pythagoras

By Substitution


Subtract 64 from both sides


Take square roots of both sides




The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such

From trigonometry


Also from trigonometry






Answer:
C
Step-by-step explanation:

OR 
x=2 and 3
Hope this helps!
Jeremy=x
Older sister=x+5
younger sister=x+5-9 or x-4
x+(x+5)+(x-4)=49
combine like terms
3x+5-4=49
3x+1=49
subtract 1 from both sides
3x=48
divide both sides by 3
x=16
Jeremy=16
Older sister=16+5=21
younger sister =16-4 or 16+5-9=12
J=16
OS=21
YS=12
A point cannot precisely be defined