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horrorfan [7]
3 years ago
10

A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

Answer:

h(t) = - 16t² + 96t

Step-by-step explanation:

A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.

So, it initial height, h_0 = 0 ft. and initial velocity v_0 = 96 feet/sec.

Now, the quadratic function, h(t), that shows the height, in feet, of the soccer ball, t seconds after it was kicked will be given by the general equation

h(t) = - 16t^{2} + v_0t + h_0

⇒ h(t) = - 16t² + 96t + 0

⇒ h(t) = - 16t² + 96t (Answer)

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Pani-rosa [81]

Answer:

0.6 is the probability of success of a single trial of the experiment

Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by P(Z>\frac{(25-27)}{3.29})

What is the probability of success of a single trial of this experiment?

Options:

  • 0.07
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Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

\mu =\frac{np}{\sigma}=\sqrt{np(1-p)}

now,

Z=\frac{X-\mu}{\sigma}

so,

by comparing with P(Z>\frac{(25-27)}{3.29}), we get:

μ=np=27

\sigma=\sqrt{np(1-p)} =3.29

put np=27

we get:

\sigma=\sqrt{27(1-p)} =3.29

take square on both sides:

10.8241=27-27p

27p=27-10.8241

p=0.6

Which is the probability of success of a single trial of the experiment

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3 years ago
_(9)=(2(1-2(2)^(9)))/(1-2(2))<br><br><br>PLEASE HELP ME OUT.
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Answer:

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Step-by-step explanation:

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There are 5 letters

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so 5 * 4 = 20 possibilities
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