All categories

2 years ago

Giving Brainiest to who gets it right please hurry though.

1 answer:

kramer2 years ago

8 0

1. 2.50x + 5 = C
2.50(4.1) + 5 = C
$15.25

2. 15.25(1.15)
$17.54

3 B, I believe but dont quote me.

4. 206 / 60 + 30
236 minutes

You might be interested in

The leg of a right triangle is 3 units and the hypotenuse is 4 units. What is the length, in units, of the other leg of the tria

Free_Kalibri [48]

Answer:

Step-by-step explanation:

This is honestly a pure guess, but I am guessing they want you to find a perfect triangle, and 3,4,5 is the smallest perfect triangle. Considering they also said it was a right triangle, I strongly beleive the answer is 5.

6 0

3 years ago

Read 2 more answers

Use a table to show the sample space of two-digit numbers using the digits 1,4,5,9. Use the column label as the tens digit and t

Lesechka [4]

Answer:

Step-by-step explanation:

7 0

2 years ago

In the town of sleepy Oak. the fine for speeding ticket is $32.65 + s dollars. Where s is the miles per hour over the speed limi

Mkey [24]

A: 38.4 - 25 = 13.4
13.4 + 32.65 = $46.05

B: 50.15 - 32.65 = 17.5
17.5 + 25 = 42.5 mph

5 0

3 years ago

Mark is adding X and -4. He finds the LCD to be 3x. What should he do next to find the sum?

MariettaO [177]

Answer:

Step-by-step explanation:

8 0

2 years ago

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

$\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666$

Second step. <u>Calculate the standard deviation</u>

$\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}$

$\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}$

$\sigma=\sqrt{17.815}=4.22$

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

$\bar X \pm t\frac{\sigma}{\sqrt n}$

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0

2 years ago