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slamgirl [31]
3 years ago
14

P

Mathematics
1 answer:
Lerok [7]3 years ago
3 0

Answer:

MOP = 62

NOP = 62

Step-by-step explanation:

sorry the answer is tilted

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A pizza shop charges $12 per pizza, p, and $4 for delivery. The expression that represents the price of a delivery is __________
lukranit [14]

Answer:

16

Step-by-step explanation:

4 0
3 years ago
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A graduated commission employee makes 3.5% interest on the first $50,000 in sales and 6.5% interest on all sales over $50,000. W
Dominik [7]
<span>b. (0.035)(50,000) + (0.065)(31,500)</span>
3 0
4 years ago
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The length of a rectangular mural is 2ft. more than three times the width the area is 165 sq. ft. Find the Width And Length
olga nikolaevna [1]
We know that the formula for the area of a rectangle is: 

A=lw 

We know that the area is 165. Now we need to solve for the dimensions. 

Let the width of the rectangle be "x"

Then the length of the rectangle is 3x+2 

Substitute. 

(3x+2)(x)=156 

Multiply the terms. 

3x^2+2x=156 

Bring the 156 over. 

3x^2+2x-156=0 

We have to use the quadratic formula to solve this now. Let us restate it: 

x= \frac{-b± \sqrt{b^2-4ac} }{2a}

Now I'm going to fast forward this because all the rest is boring stuff and substitution. The answer is: 

\frac{ \sqrt{469}-1 }{3}

Since we cannot have a negative answer, we must cancel out the other answer, which I did not include. 

Hope this helped! :) 

~Cam943, Junior Moderator
5 0
4 years ago
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Can u help with the second problem I have no idea what to do plzzzzz!!
fredd [130]

Answer: 5:8

Step-by-step explanation:

8 0
3 years ago
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A car was valued at $39,000 in the year 1995. The value depreciated to $11,000 by the year 2003.
denis23 [38]

Answer:

14.6328% , $5836.03

Step-by-step explanation:

Here we are going to use the formula

A_{0}(1-r)^n = A_{n}

A_{0} = 39000

r=?

A_{8} = 11000

n=8

Hence

39000(1-r)^8 = 11000

(1-r)^8 = \frac{11000}{39000}

(1-r)^8 = 0.2820

(1-r) = 0.2820^{\frac{1}{8}

(1-r) = 0.2820^{0.125}

(1-r) = 0.8536

(1-0.8536=r

r = 0.1463

Hence r= 0.1463

In percentage form r = 14.63%

Now let us see calculate the value of car in 2003 that is after 12 years

we use the main formula again

A_{0}(1-r)^n = A_{n}

A_{0} = 39000

r=0.1463

A_{12} = ?

n=12

39000(1-0.14634)^{(12} = A_{12}

39000(0.8536)^{12} = A_{12}

39000*0.1497 = A_{12}

A_{12}=5840.34

Hence the car's value will be depreciated to $5840.34 (approx) by 2003.

5 0
3 years ago
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