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3 years ago

If ƒ(x) varies directly with x and ƒ(x) = 32 when x = -8, then what is ƒ(x) when x = 4?

Mathematics

1 answer:

wlad13 [49]3 years ago

7 0

$f(x)=kx\\
32=-8k\\
k=-4\\
f(x)=-4x\\\\
f(4)=-4\cdot4=-16$

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Part B)

The graph of the equation is attached below.

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