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Viefleur [7K]
3 years ago
14

If ƒ(x) varies directly with x and ƒ(x) = 32 when x = -8, then what is ƒ(x) when x = 4?

Mathematics
1 answer:
wlad13 [49]3 years ago
7 0
f(x)=kx\\
32=-8k\\
k=-4\\
f(x)=-4x\\\\
f(4)=-4\cdot4=-16
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