All categories

2 years ago

1/3 divided by 1/8 a, 1/24 b. 3/8 C. 2 and 2/3 d. 24

Mathematics

2 answers:

Degger [83]2 years ago

5 0

The answer is B. 3/8

Ilia_Sergeevich [38]2 years ago

5 0

The answer is b 3/8 is the answer

You might be interested in

Kia stuffs 228 envelopes in an hour. What is the average number of envelopes Kia stuffs per minute?

stich3 [128]

Well, you already know how much she stuff per hour, but you still need to find out how much per minute. And in one hour, there are 60 minutes.

So you divide the amount in an hour by 60 minutes, meaning you divide : 228 ÷ 60 = ?

And once divided, you get 3.8. So that would mean that she stuffs 3.8 envelopes per one minute, so that means nearly 4, but since you aren't asked to round, I'd say to just go for the average rate, which is 3.8

5 0

2 years ago

Read 2 more answers

Please help! 10 PTS!

Valentin [98]

5/2+2/3+n=1/6
5/2=15/6
2/3=4/6
15/6+4/6+n=1/6
19/6+n=1/6
n=1/6-19/6
n=-18/6
n=-3
So, your answer is -3

7 0

2 years ago

Read 2 more answers

Can someone help me? this is extremely important for me to complete!

Nataliya [291]

Answer:

Question 1: A,B,D,F

Queation2: the order is 2,3,1

Question3:A

Question4:A

Step-by-step explanation:

8 0

3 years ago

4x+1=5<br> Just a test have fun with free points!

ss7ja [257]

Answer:

x = 0.666(Repeating)

Step-by-step explanation:

4x+1=5

Subtract 1 from both sides

4x=6

Divide both sides by 4

x = 0.666(Repeating)

7 0

2 years ago

Read 2 more answers

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

9 months ago