They won’t let it be on your computer, knowing it well give you answers
Answer:
The correct answer to the following question will be "Peak capacity" and "Bandwidth starvation".
Explanation:
Peak capacity has been used to characterize the gradient aqueous phase separation efficiency or performance. It represents the overall conceptual number of operations or components which can be isolated consistently with something like a given set of analytical circumstances and column with
⇒ Rs =1 (Figure 1 and Equation 1)
Certain traffic competing at its policies for the available or unused bandwidth will theoretically enable classes with lower value rates to starve to bandwidth.
Due to these activities, Sharon is concerned about "Bandwidth starvation" and "Peak capacity".
Answer:
The <em>break</em> keyword is how you interrupt a while loop.
the syntax looks like this ↓
Python ↓
while <em>true</em>:
<em>break</em>
Java script ↓
while (<em>true</em>);
<em>break</em>
Explanation:
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Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).
