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Xelga [282]
2 years ago
8

Convert the measurement to the specified five unit round to 2 decimal Place necessary

Mathematics
1 answer:
jekas [21]2 years ago
8 0

Answer:

50.31 yards

Step-by-step explanation:

divide the length value by 914.4

46,000/914.4 = 50.31

Mark brainliest please!

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Pls help<br> First, correct answer will get brainliest
kozerog [31]

Answer:

A for the first one.

Second one, I'm not sure, but I'd guess it'd be A

Step-by-step explanation:

7 0
3 years ago
Evaluate a2 - 6 for a = 4 and b = 17
Natalija [7]

Answer:

The answer is -94 but where is b

Step-by-step explanation:

2(4)-6(17)=-94

7 0
2 years ago
Find the value or X. Round your answer to the nearest tenth.
RSB [31]

Answer:

x = 9.3

Step-by-step explanation:

tan 25° = x/20

0.4663 = x/20

x = 9.3

5 0
2 years ago
SOLVE APPLICATION USING ALGEBRA. TYPE THE EQUATION OR INEQUALITY AND PLEASE SHOW WORK. a) A rectangle with perimeter 18 cm has l
alekssr [168]

Answer:

w=2\\l=7

Step-by-step explanation:

l+l+w+w=18\\\\2w+3=l\\\\2w+3+2w+3+w+w=18\\6w+6=18\\6w=12\\w=2\\\\2w+3=l\\2*2+3=l\\4+3=l\\l=7

4 0
3 years ago
Read 2 more answers
In 1985, there were 285 cell phone subscribers in Arlington. The number of subscribers increased by 75% per year since 1985. Fin
ANTONII [103]

Answer:

The number of subscribers in 2008 is 110,845,988

Step-by-step explanation:

The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.

N(t) = N(0)(1+r)^{t}

And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.

In 1985, there were 285 cell phone subscribers in Arlington.

This means that N(0) = 285

The number of subscribers increased by 75% per year since 1985.

This means that r = 0.75

So

N(t) = 285(1.75)^{t}

Find the number of subscribers in 2008.

2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).

N(23) = 285(1.75)^{23} = 110,845,988

The number of subscribers in 2008 is 110,845,988

8 0
3 years ago
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