3 years ago

If 3x^2+3y^2=42 and xy =-15.Find the value (x-y)^2

Mathematics

1 answer:

Alexxandr [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Given, 3x^2 + 3y^2 = 42

=>3(x^2 + y^2) = 42 =>x^2 + y^2 = 42/3= 14

Thus,

= (x - y)^2

= x^2 + y^2 - 2xy

= (x^2 + y^2) - 2xy

= 14 - 2(-15)

= 14 + 30

= 44

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