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Vedmedyk [2.9K]
3 years ago
15

If 3x^2+3y^2=42 and xy =-15.Find the value (x-y)^2

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0

Answer:

44

Step-by-step explanation:

Given, 3x^2 + 3y^2 = 42

=>3(x^2 + y^2) = 42 =>x^2 + y^2 = 42/3= 14

Thus,

= (x - y)^2

= x^2 + y^2 - 2xy

= (x^2 + y^2) - 2xy

= 14 - 2(-15)

= 14 + 30

= 44

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Answer:  NO

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In order for the function to be one-to-one, it must pass the vertical line test AND the horizontal line test.

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The horizontal line test is where you draw a horizontal line anywhere and the line will not intersect the graph more than one time.  In other words, the function cannot contain a duplicate y-value.

The graph provided passes the vertical line test but fails the horizontal line test. <em>One example is that there are two x-intercepts.</em>

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Natali5045456 [20]

Answer:

0 = a

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You next subtract the a from both sides.

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If i am correct, these values should add to 360, so I do it by

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