Can someone help me with this one question please thank you

Mathematics

1 answer:

matrenka [14]3 years ago

8 0

Option 3 is the correct answer just use foil to multiply

F irst
O uter
I nner
L ast

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(2x^2+3x-8)+(3x^2+9x+17)-(5x^2-15)

Lelechka [254]

Answer:

12(x+2)

Step-by-step explanation:

(2x^2+3x-8)+(3x^2+9x+17)-(5x^2-15)

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4 years ago

INEQUALITIES <br> How can i graph 2x - 5 + 4x > 2x - 1 on a number (or cartesian) plane.

zubka84 [21]

So you need to replace X with a number, let’s say 4 in this example. 2 x 4 - 5 + 4 x 4 > 2 x 4 - 1 which is basically 19>7

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2 years ago

Ar if and Keisha go to a restaurant for dinner.Their meals total $13.75 the tax is 5% how much tax is added to the bill?

Jlenok [28]

0.6875 if i am wrong i am sorry

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3 years ago

Three friends each have some ribbon. Carol has 54 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of rib

Nastasia [14]

1 ft = 12 inches......1 yd = 36 inches

carol has 54 inches
Tino has 7.5 ft......7.5 * 12 = 90 inches
baxter has 3.5 yds......3.5 * 36 = 126 inches
for a total of : (54 + 90 + 126) = 270 inches total <===

1 ft = 12 inches....so 270 inches = 270/12 = 22.5 ft <==
1 yd = 36 inches..so 270 inches = 270/36 = 7.5 yds <==

5 0

3 years ago

Find the number if: 4.5% of it is 23% of 45

Usimov [2.4K]

Well, let's say the number is "x", so "x" is the 100%.

now, what the dickens is 23% of 45 anyway?

if we take 45 to be the 100%, what is its 23%?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
45&100\\
a&23
\end{array}\implies \cfrac{45}{a}=\cfrac{100}{23}\implies \cfrac{45\cdot 23}{100}=a\implies 10.35=a$

ok, well, we know then that 4.5% of "x" is 10.35, we also know that "x" is the 100%, what is "x" anyway?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
x&100\\
10.35&4.5
\end{array}\implies \cfrac{x}{10.35}=\cfrac{100}{4.5}\implies x=\cfrac{10.35\cdot 100}{4.5}$

3 0

4 years ago

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