5(2x + 3y) - 4(3x - 5y)
5(2x) + 5(3y) - 4(3x) + 4(5y)
(10x + 15y) + (-12x + 20y)
(10x - 12x) + (15y + 20y)
-2x + 35y
Answer:
D)
because thats the only answer that would make sence.
Answer:
$37.05
Step-by-step explanation:
If you take 15% and 20% you get (15%+20%) which is 35%, then you take 100%-35% you get 65%, 65% of 57 is 37.05.
Thus Your Answer: $37.05
5x-9y=-65
10x-3y=20
Multiple the first equation by 2
10x-18y=-130
10x -3y=20
Then subtract the two equations to get rid of the x
21y=-150
Divide the -150 by 21
Y=-7.14
Plug the y into the original equation. (Either one)
5x-9(-7.14)=-65
5x-64.28=-65
Then add 64.28 to the -65
5x=-0.72
Divide by 5
X=-0.144
I hope this is right
The plane will end up flying 5.02°.
The plan's speed relative to the ground will be 645.91 km/hr.
Solution:
Use the cosine formula,

Substitute the given values in the formula,




Taking square root on both sides, we get
R = 645.91 km/hr
This is the grouped speed of the aircraft.
To find θ use sine rule.


Do cross multiplication, we get


sin θ = 0.0875
θ = 5.02°
This is known as the drift angle and is the correction the pilot should apply to remain on course.
The heading is the direction the aircraft's nose is pointing which is
The track is the actual direction over the ground which is θ = 5.02°
An alternative method to this would be to separate each vector into vertical and horizontal components and add.
The resultant can be found using Pythagoras.