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ozzi
2 years ago
5

6. How many 4 digit odd numbers can be formed if no digit can be repeated?

Mathematics
1 answer:
ale4655 [162]2 years ago
6 0
1, 3, 5, 7, 9 are the possible digits

meaning you have 5! possible combinations or 120 combinations
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The linear function f(x) = 0 5x + 80 represents the average test score in your math class, where x is the number of the test tak
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Step-by-step explanation:

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The local home improvement store wants to increase their inventory. Last year 40 lawn mowers cost them $4,776.
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40 mowers = $4,776

Multiply the above equation by 3
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The dot plots show rainfall total for several spring storms in highlands areas an lowlands areas what is the median rainfall for
tankabanditka [31]

*See attached picture showing the dot plots referred to

Answer:

16mm

Step-by-step Explanation:

Given the dot plot showing rainfall for Highlands storms, we can find out the median rainfall for Highlands storms by mere observing the dot plot and locating where the middle value falls within the data set that is represented on the dot plot.

Thus, we have 44 data sets that is being represented on the plot, with one dot representing one data set for rainfall. This means, since the total number of data set is even, our median lies between the 22nd and the 23rd dot or data set that is being plotted.

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2(3x+2)and6+4x what is the answer
Andreyy89

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Step-by-step explanation:

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2 years ago
Solve the rational function of (check image) and check for extraneous solutions
Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

\frac{5}{x}=\frac{4x+1}{x^2}

Solving the rational function

\frac{5}{x}=\frac{4x+1}{x^2}

Apply fraction across multiply: if \frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5x^2=x\left(4x+1\right)

Subtract x(4x+1) from both sides

5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)

Simplify

5x^2-x\left(4x+1\right)=0

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

so

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x=0\quad \mathrm{or}\quad \:x-1=0

Thus, the solution to the equation is:

x=0,\:x=1

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0
3 years ago
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