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rusak2 [61]
3 years ago
10

Helpp plsss!!!! I've to submit ASAP

Mathematics
2 answers:
alexandr1967 [171]3 years ago
8 0
i don’t rly remember surface area i’m sorry i couldn’t help
guapka [62]3 years ago
6 0
The answer to 6. Is the height is 8.5
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Find the area of the polygon. Figure ABCDE is shown. A is at 6, 0. B is at negative 4, 5. C is at 2, 5. D is at 2, 9. E is at 6,
kondaur [170]

This question is incomplete. The attached image was obtained online

Answer:

41 square units

Step-by-step explanation:

Looking at diagram that was attached, we can see that the Polygon s the combination of a square and a triangle.

In square CDEF we have:

The lengths of the side of the square= 4 units

Hence, the area of square is: length ²

Area of square= 4²

=16 square units

Also, in ΔBFA we have:

The base of the triangle is calculated as

=6 + 4= 10 units

height of the triangle is: FA= 5 units

The formula for Area of a triangle = 1/2 × Base × Height

Hence, we have area of ΔBFA as:

= 1/2 × 10 × 5

Area= 25 square units

The Area of the Polygon = Area of the square + Area of the triangle

16 square units + 25 square units

= 41 square units

7 0
3 years ago
CAN SOMEONE PLEASE HELP ME I WILL GIVE BRAINLEST
bonufazy [111]
The basket ball players because the mean is higher!! Good Luck!
6 0
3 years ago
Read 2 more answers
Use the table to locate the location with the greatest amount of rain and the location with the least amount of rain. What is th
Alisiya [41]

Answer:

can you show us the table?

Step-by-step explanation:

5 0
3 years ago
What is the equation of the line that began with a y-intercept of (0,4), was shifted up 3 units, and is perpendicular to y = 3/4
timama [110]

Answer:

Option A

y=-4/3x+7

Step-by-step explanation:

To solve this, we need to understand the various components of the equation of a straight line.

A straight line has the equation: y =mx + c

<em>m</em> is the slope and<em> c</em> is the intercept on the y-axis. If we can get these two components, we can figure out the equation for the new line.

Calculating the slope, <em>m</em>

To obtain the slope of the new line, we use the fact that it is perpendicular to the slope of the line y = 3/4x-2.

This means that

3/4 X <em>m</em> = -1

<em>m</em> = -4/3

To obtain the intercept, <em>c</em>

The intercept can be obtained by adding 3 to the y-component of (0, 4).

This will give (0, 7). Hence the intercept c will be 7.

Therefore, the equation of the line will be y = -4/3x+7. Option A

7 0
3 years ago
A radio station signal covers a circular area out from the signal tower. It gets weaker the farther away your are. The local sta
valentinak56 [21]

Answer:

1. We would hear better at Dunkin's since its distance from the radio station is the shortest.

2. McDonald's is out of range of the radio station since its distance is greater than the range of the radio station.

Step-by-step explanation:

1) Will we hear it better at Zaxby's (2,-4), McDonalds (4, -4), or Dunkin' (-3,3). Show work to support your decision and explain your reasoning.

We need to find the distance of each point from the tower.

The shorter the distance from the radio station the better the signal.

The distance between two points (x₁, y₁) and (x₂, y₂) is given by d = √[(x₂ - x₁)² + (y₂ - y₁)²].

With (x₁, y₁) = (0, 0) the location of local station WDHS

For Zaxby's distance located at (2, -4) = (x₂, y₂)

So, d₁ = √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[(2 - 0)² + (-4 - 0)²]

= √[(2)² + (-4)²]

= √[4 + 16]

= √20

= √(5 × 4)

= √5 × √4

= 2√5

= 4.47 miles

For McDonald's distance located at (4, -4) = (x₂, y₂)

So, d₂ = √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[(4 - 0)² + (-4 - 0)²]

= √[(4)² + (-4)²]

= √[16 + 16]

= √32

= √(16 × 2)

= √16 × √2

= 4√2

= 5.66 miles

For Dunkin's distance located at (-3, 3) = (x₂, y₂)

So, d₃ = √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[(-3 - 0)² + (-3 - 0)²]

= √[(-3)² + (-3)²]

= √[9 + 9]

= √18

= √(9 × 2)

= √9 × √2

= 3√2

= 4.24 miles

<u>Since Dunkin's distance, d₃ = 4.24 is the least distance from the radio station and is within range of 5 miles, we would hear better at Dunkin's.</u>

2) Are any of these location outside the range of the radio station? If so, which one(s). Defend your decision mathematically.

The radio station is outside of range if its distance is greater than 5 miles. That is, d > 5 miles.

So, we calculate the distance of each point from the radio station.

With (x₁, y₁) = (0, 0) the location of local station WDHS

For Zaxby's distance located at (2, -4) = (x₂, y₂)

So, d₁ = √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[(2 - 0)² + (-4 - 0)²]

= √[(2)² + (-4)²]

= √[4 + 16]

= √20

= √(5 × 4)

= √5 × √4

= 2√5

= 4.47 miles

For McDonald's distance located at (4, -4) = (x₂, y₂)

So, d₂ = √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[(4 - 0)² + (-4 - 0)²]

= √[(4)² + (-4)²]

= √[16 + 16]

= √32

= √(16 × 2)

= √16 × √2

= 4√2

= 5.66 miles

For Dunkin's distance located at (-3, 3) = (x₂, y₂)

So, d₃ = √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[(-3 - 0)² + (-3 - 0)²]

= √[(-3)² + (-3)²]

= √[9 + 9]

= √18

= √(9 × 2)

= √9 × √2

= 3√2

= 4.24 miles

<u>So, for each of the distances calculated above, only McDonald's distance, d₂ = 5.66 miles > 5 miles. </u>

<u>So, McDonald's is out of range of the radio station.</u>

5 0
3 years ago
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