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Elanso [62]
3 years ago
5

I WILL GIVE BRAINLIEST

Mathematics
1 answer:
stealth61 [152]3 years ago
4 0
The answer is a. A and B
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Please help I’m not good at this
tia_tia [17]
23/4

Step by step:
5/1 + 3/4
5/1 • 4 = 20/4
20+3/4
23/4
8 0
4 years ago
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The lengths of the sides of a square are 5 cm. find the length of the diagonal
jenyasd209 [6]

Answer:

square root (50) = 7.071

Step-by-step explanation:

Using Pthagoras' theorem, the diagonal length is \sqrt{x} ax^{2} +bx^{2}.

Therefore, the diagonal length is the square root of 5^2+5^2,

= \sqrt{x} 25+25

= \sqrt{x} 50

= 7.071

8 0
3 years ago
1. Grace was given the equation 2x + 20 = 15. She decides to add 10 to both sides of the equation. a.) Is that an acceptable mov
vlada-n [284]

9514 1404 393

Answer:

  • yes
  • 2x +30 = 25

Step-by-step explanation:

Adding the same number to both sides of the equation is an acceptable move. The addition property of equality tells Grace that the value of the variable will remain unchanged by such a move.

Her new equation would be ...

  2x +20 +10 = 15 +10

  2x +30 = 25 . . . . the result of Grace's move

_____

<em>Additional comment</em>

There may be very good reasons why Grace would want to do that. If solving the equation is Grace's intent, that move would be counterproductive. For the purpose of solving the equation, it would be more productive to either subtract 20 from both sides, or divide both sides by 2. These steps would give, respectively, ...

  2x = -5

  x +10 = 7.5

6 0
3 years ago
The following table shows the monthly charges for subscribing to the local newspaper.
Ostrovityanka [42]
D. independent -- Number of Months
dependent -- Total Cost

The dependent Variable depends on the independent variable so, as the number of months change, the total cost changes.
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3 years ago
Mei is trying to list as many prime numbers as she can for a challenge problem for her math class. She finds
Svet_ta [14]
Hello,

Since the degree of a polynomial is the highest exponent present, the degree of Mei’s polynomial should be 2.
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