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3 years ago

11

yesterday at football practice, Han made 12 of his field goal attempts. Today he made 75% as many as he did yesterday. How many

attempts did han make today?

2 answers:

SVEN [57.7K]3 years ago

8 0

Answer:

answer is 0.16

Step-by-step explanation:

12/75=0.16 it's division if u don't understand what i did srry

solong [7]3 years ago

7 0

Answer:

9

Step-by-step explanation:

.75 x 12 = 9

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After eating 75% of the chocolates in a box, Dev found 6 chocolates remaining. How many chocolates were there in the box origina

Virty [35]

Answer:

24

Step-by-step explanation:

Let total number of the chocolates be x.

25% of x = 6 (because 100 - 75 = 25% of chocolates left).

25/100 x x = 6

x = 600/25

x = 24

Hence, 24 is the total amount of chocolates.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

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2 years ago

Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti

alukav5142 [94]

Answer:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3$

Step-by-step explanation:

We want to evaluate the limit:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}$

To do so, we can divide everything by <em>x</em>². So:

$=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}$

Now, we can apply direct substitution:

$\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}$

Any constant value over infinity tends towards 0. Therefore:

$\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3$

Hence:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3$

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3<em>x</em>²<em>, </em>and in the denominator it is <em>x</em>². So:

$\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}$

Simplify:

$\displaystyle =\lim_{x\to\infty}3=3$

The limit of a constant is simply the constant.

We acquire the same answer.

6 0

3 years ago

An urn contains 12 balls, of which 4 are white.

wel

Answer:

a) $\frac{1}{3}$

b) $\frac{4}{12}\,,\,\frac{4}{11}\,,\,\frac{4}{10}\,,...$

Step-by-step explanation:

Number of balls in the urn = 12

Number of white balls in the urn = 4

So, number of balls which are not white = 12 - 4 = 8

We know that probability = No. of outcomes/Total number of outcomes

Let $A_i\,,\,B_i\,,\,C_i$ denotes the event of getting white ball by A, B and C

a) each ball is replaced after being drawn.

Probability = Number of white balls/Total number of balls

Solution: $P(A_i)=P(B_i)=P(C_i)=\frac{4}{12}=\frac{1}{3}$

b)the balls that are withdrawn are not replaced.

Solution:

If A wins: $P(A_1)=\frac{4}{12}=\frac{1}{3}$

If A lost and B wins: $P\left ( B_1|A_1^{c} \right )=\frac{4}{11}$

If A and B lost and C wins: $P\left ( C_1|A_1^{c}\,B_1^{c} \right )=\frac{4}{10}$

and so on....

4 0

4 years ago

Use the box plots comparing the number of males and number of females attending the latest superhero movie each day for a month

Maksim231197 [3]

Answer:

Part A:

The interquartile range is approximately 10

Part B:

The difference between the median values for each data set is approximately 6

Part C:

i) More widely distributed and concentrated to the beginning of the month

The better measure of the center for the male dataset is the median

ii) The skewed distribution

The mean is the better measure of center for the dataset

Part D;

A possible reason for the outlier is by chance

Step-by-step explanation:

Part A:

The interquartile range, IQR, is the width of the box in the box plot = The difference between the third quartile, Q₃ and the first quartile, Q₁ = Q₃ - Q₁

From the diagram, Q₃ ≈ 13, Q₁ ≈ 3

∴ The interquartile range, IQR = 13 - 3 = 10

Part B:

From the diagram of the box plot, the median value, of the males, M-Q₂ ≈ 12

The median value for the females, F-Q₂ ≈ 18

The difference, M-Q₂ - F-Q₂ = 18 - 12 ≈ 6

The difference between the median values for each data set, d = M-Q₂ - F-Q₂ ≈ 6

Part C:

i) The distribution of the of the male dataset for the male has more data on the left of the box plot, with the median located approximately at the center and an outlier at end of the month

The better measure of the center for the male dataset is the median

ii) The distribution of the dataset for the females is skewed (concentrated on the right of the plot). The data set has no outlier and the first quartile is 0, while the third quartile corresponds with the maximum value at 21, the first quartile is 15 and the IQR is approximately 6

The better measure of center for the dataset is the mean, as the difference between the value of the first quartile, 0, and the other data points is more accounted for by the mean

Part D;

The possible reason for the outlier in the male dataset can be attributed to chance

4 0

3 years ago

Find the value of x. Express your answer in simplest radical form

Sever21 [200]

Answer:

Use Pythagorean Theorem which is a squared (one of the numbers thats side is with the 90° angle) plus b squared (the other number thats side is next to the 90° angle) equals c squared (the hypotenuse).

Step-by-step explanation:

Use Pythagorean Theorem which is a squared (one of the numbers thats side is with the 90° angle) plus b squared (the other number thats side is next to the 90° angle) equals c squared (the hypotenuse).

6 0

4 years ago