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Talja [164]
3 years ago
10

In the diagram, triangle GEF and triangle HEF are congruent. What is the value of x?

Mathematics
2 answers:
Harrizon [31]3 years ago
8 0
2(x+2) = 60
x+2 = 30
x = 28
The correct answer is C
serious [3.7K]3 years ago
4 0

Answer:

The correct answer is C  28

Step-by-step explanation:


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Expand (2x + 3)^5 using the Binomial Theorem and Pascal’s triangle. Show all steps.
kari74 [83]

Answer:

32x⁵ + 240x⁴ + 720x³ + 1080x² + 810x + 243

Step-by-step explanation:

(2x + 3)⁵

₅C₀ (2x)⁵ (3)⁰ + ₅C₁ (2x)⁴ (3)¹ + ₅C₂ (2x)³ (3)² + ₅C₃ (2x)² (3)³ + ₅C₄ (2x)¹ (3)⁴ + ₅C₅ (2x)⁰ (3)⁵

Use Pascal's triangle to find nCr.

\left\begin{array}{c}1\\1\ 1\\1\ 2\ 1\\1\ 3\ 3\ 1\\1\ 4\ 6\ 4\ 1\\1\ 5\ 10\ 10\ 5\ 1\end{array}\right

1 (2x)⁵ (3)⁰ + 5 (2x)⁴ (3)¹ + 10 (2x)³ (3)² + 10 (2x)² (3)³ + 5 (2x)¹ (3)⁴ + 1 (2x)⁰ (3)⁵

(2x)⁵ + 15 (2x)⁴ + 90 (2x)³ + 270 (2x)² + 405 (2x)¹ + 243

32x⁵ + 240x⁴ + 720x³ + 1080x² + 810x + 243

7 0
3 years ago
Michael bought 0.44 pound of slice turkey. what is the value of the digit in the hundredths place?
jarptica [38.1K]

Answer:

4

Step-by-step explanation:

You have 0.44

0 is in the ones place

4 is in the tenths place (0.4)

And the other 4 is in the hundredths place (0.04)

8 0
3 years ago
Read 2 more answers
Can you please answer everything. What fraction every letter on their can run in a minute. Reward brainiest answer: 15 points
oksian1 [2.3K]
Student B:
1/2 / 4
= 1/2 x 1/4
= 1/8

student A:
2/3 / 6
= 2/3 x 1/6
= 1/9

student C:
4/5/ 8
= 4/5 x 1/8
= 1/10


answer
student B: 1/8 of a mile per minute
student A: 1/9 of a mile per minute
student C: 1/10 of a mile per minute
8 0
3 years ago
Geometry math question no Guessing and Please show work thank you
vesna_86 [32]

First let us find the length of JN

JN =JK +KN

JN = 82+105 = 187

JN=187..............(1)

UC= JN -( JH +HU+CN)

We are given :

JH= 22, HU = 96 and CN = 51

plugging all the values we get

UC = 187-( 22+96+51)

UC =187 -169

UC = 18

Answer is UC =18 ( option B)

8 0
3 years ago
Daily-high temperature measurements for 40 consecutive days are recorded for a particular city. The mean daily-high temperature
Vesnalui [34]

Answer:

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

p_v =P(t_{39}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.  

(D) P-val=0.021, fail to reject the null hypothesis

Step-by-step explanation:

1) Data given and notation  

\bar X=21.5 represent the mean for the temperatures

s=1.5 represent the sample standard deviation

n=40 sample size  

\mu_o =22 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 22C, the system of hypothesis would be:  

Null hypothesis:\mu \geq 22  

Alternative hypothesis:\mu < 22  

If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

P-value

We can calculate the degrees of freedom like this:

df=n-1=40-1=39

Since is a one left tailed test the p value would be:  

p_v =P(t_{39}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.  

The best option would be:

(D) P-val=0.021, fail to reject the null hypothesis

5 0
3 years ago
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