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3 years ago

5

A middle school is supplied with 3 bottles of germ x for every 2 students. If the middle school has exactly 856 students, how ma

ny bottles of germ x must be supplied? _________ bottles of germs

1 answer:

Shkiper50 [21]3 years ago

8 0

1,284 because you have to divide the students in half because it is every two students. And each pair gets three bottles.

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The table shows the low temperatures in Alto for 5 days.What is the average low tempreature

satela [25.4K]

If you add all the numbers on the right together you get -35 then you divide by 5 which gives you the average of -7*F

4 0

3 years ago

twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only

Karolina [17]

donuts and cream puffs were 45 & 4 respectively !

<u>Step-by-step explanation:</u>

Here we have , twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only 5 less than the number of donuts We need to find how many donuts and cream puffs were there . Let's find out:

Let number of donuts and cream puffs are x & y respectively ! So ,

twice the number of donuts was only 6 less than 24 times the number of cream puffs

According to this statement equation is :

⇒ $2x=24y-6$

⇒ $x=12y-3$ ................(1)

10 times the number of cream puffs was only 5 less than the number of donuts

According to this statement equation is :

⇒ $10y= x-5$

⇒ $x=10y+5$ ................(2)

Equation (1) & (2) :

⇒ $12y-3=10y+5$

⇒ $2y=8$

⇒ $y=4$

Putting $y=4$ in $x=12y-3$ :

⇒ $x = 12(4)-3$

⇒ $x = 45$

Therefore , donuts and cream puffs were 45 & 4 respectively !

7 0

3 years ago

Heellllllllllllllllllllppppppppppppppppppppppppppp

tatyana61 [14]

The slope or also known as “m” equals 4/4 or 1 in simplified form.

4 0

3 years ago

Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex

siniylev [52]

Answer:

$\large \boxed{\sf \ \ \ p=-11 \ \ \ }$

Step-by-step explanation:

Hello,

$\alpha \text{ and } \beta \text{ are the roots of the following equation}$

$2x^2+6x-7=p$

It means that

$2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\$

And we know that

$\alpha= 2\cdot \beta$

So we got two equations

$2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1$

For $\beta =0, \ \ \alpha =0, \ \ p = -7$

For $\beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11$

I assume that we are after two different roots so the solution for p is p=-11

b) $\alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1$

So a quadratic equation with the expected roots is

$x(x-1)=x^2-x$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0

3 years ago

Please help 10 FREE POINTS!!!!

Maurinko [17]

Answer:

364.5

Step-by-step explanation:

you would need a calculator for it, unless you can do exponential math at such a degree... if you're using a PC there's a good graphing calculator at Desmos.com, it can show you how a graph looks, which shows that when n is 7, the answer is 364.5. also it wouldn't be 1093.5 because the exponent is n-1 which means that while n could be 7, you need to take away 1 before using it as an exponent.

7 0

3 years ago

Read 2 more answers