Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
13. 3(x-6)-8=-2 (you have to plug in x-6 as x in the equation
3x-18-8=-2 (distribute 3)
3x-26=-2 (combine like terms)
3x=24 (subtract 26 to both sides)
x=8 (divide 3 to both sides)
14. -2(3(5y+5)=-4
-2(15y+5)=-4
-30y-10=-4
30y=6
y=1/5
15. (3x-5) +2x = 90
16. Let m be the number of minutes
0.75m+32 = 47
Using this equation you can find the number of minutes.
0.75m = 15 ( subtract 32 to both sides)
m= 20 (divide 0.75 to both sides)
Vera called 20 minutes beyond her allowed minutes.
Here I hope that this helped you out hon :)
Explanation:
The slope-intercept form of a line is:
y=mx+b
where:
m is the slope of the line
b is the y-intercept
We are given that m=4 and the line passes through (7,2).
∴2=4⋅7+b
2=28+b
b=−26
Therefore the equation of the line is:
y=4x−26
graph{y=4x-26 [-1.254, 11.23, -2.92, 3.323]}
