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ExtremeBDS [4]
3 years ago
11

HELP I NEED ANSWER BEFORE 11 59

Mathematics
2 answers:
almond37 [142]3 years ago
7 0
I think it’s 1 because there’s 9 shirts left and atleast one of them has to be green
Svetach [21]3 years ago
6 0
I believe the answer is 5
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Can someone please help me here
WARRIOR [948]

\begin{cases} f(x)=3-3x\\ g(x)=x^2 \end{cases}\qquad \qquad \begin{array}{llll} f(~~g(x)~~)=3-3[g(x)]\\\\ f(~~g(x)~~)=3-3[x^2] \end{array} \\\\\\ f(~~g(x)~~)=3-3x^2\implies f(~~g(x)~~)=3(1-x^2)

5 0
3 years ago
The y-intercept of a function f(x) is (0, b). What is the y-intercept of f(x) + k?
Mice21 [21]

Answer:

Step-by-step explanation:

Can I follow you?

7 0
3 years ago
Read 2 more answers
Dibuja un segmento de 6cm y su mediatriz construye un triángulo con dos de sus vértices en los extremos del segmento y el tercer
yuradex [85]

Answer:

Equilátero si todos sus lados son iguales o isósceles si la base es menor que sus otros dos lados.

Step-by-step explanation:

Revisar fotografía adjunta.

Comienzas dibujando la línea de 6 cm. Luego encuentras su mediatríz, la cual está a 3 centímetros de cualquier extremo de la línea.

Luego dibujas el triángulo como se muestra en el dibujo. Dependiendo de la longitud de los lados, el triángulo podría ser equilátero si todos sus lados son iguales o isósceles si solo los dos lados inclinados son iguales y la base es diferente.

3 0
3 years ago
What is the x-coordinate for the minimum point in the function f(x) = 4 cos(2x − π) from x = 0 to x = π?
melamori03 [73]
When you are looking at a graph, a minimum point would be where the curve is decreasing, then begins to increase. Right at the point where it switches, the slope is a horizontal line, or 0. We can take the derivative is f(x), then look for all the x values where the slope (which is equal to the first derivative) is equal to zero.

f'(x) = 2 * -4sin(2x - pi)

The 2 comes from the derivative of the inside, 2x-pi.

So now set the derivative equal to 0.

-8sin(2x-pi) = 0

We can drop the -8 by dividing both sides by -8.

sin(2x-pi) = 0

This can be rewritten as arcsin(0) = 2x-pi

So when theta equals 0, what is the value of sin(theta)? At an angle of 0, there is just a horizontal line pointing to the right on the unit circle with length of 1. Sine is y/h, but there is no y value so it is just 0. If arcsin(0) = 0, we can now set 2x-pi = 0

2x = pi

x = pi/2

This is a critical number. To find the minimum value between 0 and pi, we need to find the y values for the endpoints and the critical number.

f(0) = -4

f(pi/2) = 4

f(pi) = -4

So the minimum points are at x=0 and x=pi




5 0
4 years ago
Which values of a b and c correctly complete the divison
Softa [21]

Answer:

a=4, b=6, c=5

Step-by-step explanation:

multiply by the reciprocal of 5/6, or 6/5

3 0
3 years ago
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