D has a value of 24.
V121 is 11, so 13 + 11 is 24
Answer:
The volume of the glass is 217.8 cm³
Step-by-step explanation:
If the glass were initially 4/7 full, that means 3/7 of the volume is still available to hold more juice.
Let v represent the volume of the glass.
Then (3/7)v + 70 cm³ = (3/4)v.
We need to solve this for v.
Here the LCD is 28. Thus,
(3/7)v + 70 cm³ = (3/4)v → (12/28)v + 70 cm³ = (21/28)v.
Subtracting (12/28)v from both sides, we get:
70 cm³ = (9/28)v.
We can isolate v by mult. both sides by the inverse of 9/28, which is 28/9:
(28/9)(70 cm³) = v
The volume of the glass is 217.8 cm³
Dy/dx=1/2, 1/2, 1/2 etc
So this is a linear equation of the form y=mx+b where m=dy/dx=1/2 so
y=x/2 +b, now we can use any point to solve for the y-intercept, "b", I'll use (7,0)
0=7/2 +b
b=-7/2 so
y=x/2-7/2
y=(x-7)/2
<span>A. y=secx
This problem deals with the various trig functions and is looking for those points where they are undefined. Since the only math operations involved is division, that will happen with the associated trig function attempts to divide by zero. So let's look at the functions that are a composite of sin and cos.
sin and cos are defined for all real numbers and range in value from -1 to 1.
sin is zero for all integral multiples of pi, and cos is zero for all integral multiples of pi plus pi over 2. So the functions that are undefined will be those that divide by cos.
tan = sin/cos, which will be undefined for x = π/2 ±nπ
cot = cos/sin, which will be undefined for x = ±nπ
sec = 1/cos, which will be undefined for x = π/2 ±nπ
csc = 1/sin, which will be undefined for x = ±nπ
Now let's look at the options and pick the correct one.
A. y=secx
* There's a division by cos, so this is the correct choice.
B. y=cosx
* cos is defined over the entire domain, so this is a bad choice.
C. y=1/sinx
* The division is by sin, not cos. So this is a bad choice.
D. y=cotx,
* The division is by sin, not cos. So this is a bad choice.</span>
I believe that it is C, mind you I could’ve got it wrong. It’s been awhile since I’ve done that kind of math.