Answer:
the answer is B
Step-by-step explanation:
hoped I helped:)
Answer:
30p^3−36p
Step-by-step explanation:
6(5p^3−6p)
=(6)(5p^3+−6p)
=(6)(5p^3)+(6)(−6p)
=30p3−36p
First 3 terms are a^2 + n a^(n-)1 b + n(n-1)/2 * a^(n-2) b^2
So q^2 / pr = (n^2 * a^(2n-2) * b^2 ) / (1/2 * a^n * (n(n-1) * a^(n-2) * b^2 )
= n^2 * a^2n-2 * b^2
-----------------------------------
1/2 n(n-1) * a^(2n-2) * b^2
= 2n / n - 1 as required
given p = 4, q=32 and r = 96:-
32^2 / 4*96 = 2n / n-1
2n / n-1 = 8/3
6n = 8n - 8
2n = 8
n = 4 answer
The correct answer is A) f(x) should be vertically stretched by 1.5.
This is because it is going to be rising at a much faster rate. Therefore, the slope should be more steep, which can only be done by stretching the graph. Moving it up and down would only change the initial amount she had traveled, which should always be 0.
Answer:
4(9a-4)
Step-by-step explanation:
