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taurus [48]
2 years ago
10

Help help i will mark me brill PLEASE help me i am struggling guys please

Mathematics
1 answer:
Eddi Din [679]2 years ago
4 0

Answer:

a) night, from cool land to sea

b) day, from cool sea to land

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Can you guys help me please as much as you can ^^
GalinKa [24]

Answer:

(m1) =  50

(m2)=

(m3)= 108

(m4)=

(m5)=

(m6)=

(m7)=

(m8)=

(m9)=

(m10)= 18

(m11)=

Im still adding

3 0
2 years ago
Read 2 more answers
Excellent! Move on to the 7th (or 8th if you count 0)<br> Fibonacci number.
anygoal [31]

Answer:

sorry i dont know the answer to that i just need the points

Step-by-step explanation:

8 0
3 years ago
solve this word problem leading to quadratic equation: the area of a rectangle is 60cm². The length is 11cm more than the width.
morpeh [17]

Answer:

Step-by-step explanation:

let : x The length and y the width you have this system :

xy =60....(1)

x = y+10...(2)

put the value for x in (1):  (y+10)y =60

the quadratic equation is : y² +10y - 60 = 0

Δ =b² - 4ac        a = 1        b= 10      c= - 60

Δ =10² - 4(1)(-60) = 324 =18²

y 1 = (-10-18)/2 negatif...... refused

y 2 = (-10+18)/2 =4

the width is 4

8 0
2 years ago
6 apples cost exactly the same as 9 oranges. 10 apples and 10 oranges cost $7.50. Find the cost of 1 apple and the cost of 1 ora
balandron [24]

Answer:6 apples cost exactly the same as 9 oranges. 10 apples and 10 oranges cost $7.50. Find the cost of 1 apple and the cost of 1 orange.

Step-by-step explanation:

8 0
2 years ago
For some postive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770. The value of Z is
Talja [164]

Answer:

1.16

Step-by-step explanation:

Given that;

For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.

This implies that:

P(0<Z<z) = 0.3770

P(Z < z)-P(Z < 0) = 0.3770

P(Z < z) = 0.3770 + P(Z < 0)

From the standard normal tables , P(Z < 0)  =0.5

P(Z < z) = 0.3770 + 0.5

P(Z < z) =  0.877

SO to determine the value of z for which it is equal to 0.877, we look at the

table of standard normal distribution and locate the probability value of 0.8770. we advance to the  left until the first column is reached, we see that the value was 1.1.  similarly, we did the same in the  upward direction until the top row is reached, the value was 0.06.  The intersection of the row and column values gives the area to the two tail of z.   (i.e 1.1 + 0.06 =1.16)

therefore, P(Z ≤ 1.16 ) = 0.877

8 0
3 years ago
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