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3 years ago

Find the smallest value of $x$ such that $x^2 + 10x + 25 = 8$.

Mathematics

1 answer:

Mashutka [201]3 years ago

3 0

Answer:

-5 -√8 or ≈ -7.83

Step-by-step explanation:

<u>Solving the quadratic equation, to find its roots:</u>

x^2 + 10x + 25 = 8 ⇒ The left side is perfect square
(x+5)^2=8 ⇒ Getting square root of both sides
x+5 = ± √8 ⇒ There are 2 roots
x = - 5 ± √8

<u>The smallest root is:</u>

x= -5 - √8 ≈ -7.83

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musickatia [10]

Answer:

5/3

Step-by-step explanation:

2x+3=5x-2

Subtract 2x from both sides

3=3x-2

Add 2

5=3x

Divide by three

5/3=x

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2 years ago

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3 years ago

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It takes a hose 2 minutes to fill a rectangular aquarium 8 inches long, 10 inches wide, and 14 inches tall. How long will it tak

kari74 [83]

Answer:

66 minutes, or 1 hour and 6 minutes.

Step-by-step explanation:

let us first do the rectangular aquarium:

8 x 10 = 80

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now the second box

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575 x 33 = 18975

we can divide the boxes volume:

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so all we have to do is times 33 by 2 which equals:

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2 years ago

Please help me asappp (will give brainiest!)

ryzh [129]

Answer:

TanФ=-1.793

Step-by-step explanation:

$Sin^{2} (A) + Cos^{2} (A) = 1$

$Sin(A)=\sqrt{1-Cos^{2} (A)}$

$Tan(A) = \frac{Sin(A)}{Cos(A)}$

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3 years ago

Help!! Which of the following best represents Z1 • Z2 select all that apply

AURORKA [14]

$z_1=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)$

$z_2=\sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)$

$\cos \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}$

$\sin \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}$

$\cos \left(\frac{3\pi }{4}\right)=-\frac{\sqrt{2}}{2}$

$\sin \left(\frac{3\pi }{4}\right)=\frac{\sqrt{2}}{2}\\$

$Z_1*Z_2=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)\cdot \sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)$

$=\sqrt{3}\left(\frac{\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)\cdot \sqrt{6}\left(\frac{-\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)$

On simplifying, we get

$Z_1* Z_2 =-3\sqrt{2}$

<h2>Therefore, correct option is 1st option.</h2>

3 0

3 years ago