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aleksandrvk [35]
3 years ago
14

Find the smallest value of $x$ such that $x^2 + 10x + 25 = 8$.

Mathematics
1 answer:
Mashutka [201]3 years ago
3 0

Answer:

-5 -√8  or ≈ -7.83

Step-by-step explanation:

<u>Solving the quadratic equation, to find its roots:</u>

  • x^2 + 10x + 25 = 8           ⇒ The left side is perfect square
  • (x+5)^2=8                         ⇒ Getting square root of both sides
  • x+5 = ± √8                       ⇒ There are 2 roots
  • x = - 5 ± √8

<u>The smallest root is:</u>

  • x= -5 - √8 ≈ -7.83
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Step-by-step explanation:

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sergiy2304 [10]
The answer that I got was side  WX = 12 inches

It says that WY is congruent to XY which means that they are the same. That means that XY is also 3m-4. It also says that the perimeter of the triangle is 76 inches.

With this information I set up an equation:

3m-4 + 3m-4 +m = 76

(The number on the right side is the perimeter given to us in the problem and the numbers on the left side are the 3 side lengths).

I combined like terms on the left side and ended up with:

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I added 8 to both sides of the equation and got 7m=84.

Finally I divided both sides by 7 and got m=12

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4 years ago
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