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3 years ago

9

These students that fail a single time, will withdraw (drop) from the program the month following their failure; ex. J. Doe fail

s Month 3, J. Doe withdraws before the start of Month 4.

1 answer:

dlinn [17]3 years ago

8 0

Pacencia la need pontus kamnksnbxjxjjxjxndndnxjxjnvjsbgjsiw

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How to make a word problem from 115

Korolek [52]

Answer: 80 + 35 = 115

Step-by-step explanation: just an example of a word problem you can use

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3 years ago

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Situation: a 25 gram sample of a substance that’s used for drug research has a K-value of 0.1205

Lelu [443]

The decay model is given as

$N=N_0e^{-Kt}$

The substance's half-life is the time it takes for the substance to decay to half its original amount. In other words, it's the time $t$ such that $N=\dfrac{N_0}2$ . Substituting into the model, you have

$\dfrac12=e^{-Kt}$

You can solve for $t$ now.

$\dfrac12=e^{-Kt}$
$\implies\ln\dfrac12=\ln e^{-Kt}$
$\implies-\ln2=-Kt\ln e$
$\implies\dfrac{\ln2}K=t\approx5.7523\text{ days}$

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3 years ago

Simplify this expression.<br><br> (g4)7 =

MatroZZZ [7]

Your answer is 7g^4

Hope this helps!

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3 years ago

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L.c.m of 21,24,26 what is it plz I need answers

S_A_V [24]

Answer:

LCM of 21,24 and 26 is 2184

Step-by-step explanation:

We need to find LCM of 21,24 and 26

For finding LCM divide the given numbers by a prime number if two of the numbers are divisible by that prime number

2 | 21,24,26

2 | 21,12,13

2 | 21,6,13

3 | 21,3,13

7 | 7,1,13

13 | 1,1,13

| 1,1,1

So, LCM of 21,24 and 26 is: 2 x 2 x 2 x 3 x 7 x 13 = 2184

8 0

3 years ago

2. The equation of a circle is x^2 + 2x + y^2 + 6y = 0.

pentagon [3]

Answer:

a)
${x}^{2} + 2x + {y}^{2} + 6y = 0$
${x}^{2} + 2x + 1 + {y}^{2} + 6y + 9 = 10$
${(x + 1)}^{2} + {(y + 3)}^{2} = 10$
b)
center I(-1;-3)

$radius = \sqrt{10}$

8 0

4 years ago