2. The equation of a circle is x^2 + 2x + y^2 + 6y = 0.

1 answer:

8 0

Answer:

a)
${x}^{2} + 2x + {y}^{2} + 6y = 0$
${x}^{2} + 2x + 1 + {y}^{2} + 6y + 9 = 10$
${(x + 1)}^{2} + {(y + 3)}^{2} = 10$
b)
center I(-1;-3)

$radius = \sqrt{10}$

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