Question

2. The equation of a circle is x^2 + 2x + y^2 + 6y = 0.

Answer 1

Answer:

a)
${x}^{2} + 2x + {y}^{2} + 6y = 0$
${x}^{2} + 2x + 1 + {y}^{2} + 6y + 9 = 10$
${(x + 1)}^{2} + {(y + 3)}^{2} = 10$
b)
center I(-1;-3)

$radius = \sqrt{10}$