1)<span>sixty-five hundredths
2)</span><span>twelve and thirty-one hundredths
3)</span><span>six hundred ninety-two and fourteen hundredths
4)</span><span>eighty-one and fifty-one hundredths
5)</span><span>nine hundred fourteen and eleven thousandths
6)</span>three thousand, five hundred twenty-one and <span>seventy-one hundredths
7) </span><span>fifty-six hundredths
8)</span>eight thousand, nine hundred forty-eight and <span>three hundredths</span>
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
<span>8/5 = 1.6 bag per minute
8 bags of skittles in 5 minutes
? 10 minutes
8 x 10 / 5
= 80 /5
= 16
answer
</span>1.6 bag per minute
<span>and
16 bags in 10 minutes</span>
Answer:
37
Step-by-step explanation:
h + 4g
5 + 4(8)
5 + 32 = 37
<em>x = 36</em>
- Step-by-step explanation:
<em>2x + 27 = 3x - 9</em>
<em>27 + 9 = 3x - 2x</em>
<em>x = 36</em>