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Klio2033 [76]
2 years ago
8

Volunteers at Sam's school use some of the student council's savings for a special project. They buy 8 backpacks for $8 each and

fill each backpack with paper and pens that cost $3. By how much did the student council's savings change because of this project?
The savings was changed by
dollars.
Mathematics
2 answers:
inn [45]2 years ago
8 0
Savings were changed by $88
Tpy6a [65]2 years ago
5 0

Answer:

The savings were changed by $88

Step-by-step explanation:

1 backpack costs 8 dollars and they bought 8 of them, you have to multiply 8 dollars by 8 cause there is 8 backpacks which is 64 , pen and pencils for 1 backpack costs 3 dollars , so you have to multiply 3 by 8  cause there are 8 backpacks which is 24. then you add 64 and 24 which is 88

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Step-by-step explanation:

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2 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

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The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

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3 years ago
sales associate at an electronic store earn different commission percentages based on the items they sell the table shows the to
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Answer:

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Step-by-step explanation:

7 0
3 years ago
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Answer:

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zmey [24]

Answer:

V=pi*\frac{16 h}{3}

Step-by-step explanation:

Volume of a right circular cone can be found using the equation

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