Question

(3x^-7 yz^-3)(3x)^-4

Answer 1

Answer:

The step wise solution is shown below:

Step-by-step explanation:

                $(3x^{-7} y z^{-3} ) (3x)^{-4}$

            =  $(3x^{-7} (3x)^{-4} y z^{-3} )$

            = $3^{1-4} x^{-7-4} y z^{-3}$

            = $3^{-3} x^{-11} yz^{-3}$

            = $\frac{y}{3^{3} x^{11}z^{3} }$

            = $\frac{y}{27 x^{11}z^{3} }$