Answer:
x=
2
3v−19
x=
5
−2v−19
Step-by-step explanation:
Answer:
<em>The equation of the parallel line to the given equation is </em>
<em>3 x-4 y = -4 and </em>
<em>The equation of the parallel line to the given equation is </em>

<em></em>
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given equation of the line 3 x -4 y = 7 and given point ( -4 , -2 )
<em>The equation of the parallel line to the given equation is </em>
<em>3 x - 4 y = k </em>
it is passes through the point ( -4 , -2)
3 (-4) - 4 ( -2) = k
-12 +8 = k
k = -4
<em>The equation of the parallel line to the given equation is </em>
<em>3 x- 4 y = -4 </em>
<em>Dividing '4' on both sides , we get</em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<em></em>
<u><em>Conclusion</em></u>:-
∴ <em>The equation of the parallel line to the given equation is </em>
<em>3 x- 4 y = -4 </em>
<em>and </em>
<em>The equation of the parallel line to the given equation is </em>

<em> </em>
Answer:
z=16
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−7(z−6)=−70
(−7)(z)+(−7)(−6)=−70(Distribute)
−7z+42=−70
Step 2: Subtract 42 from both sides.
−7z+42−42=−70−42
−7z=−112
Step 3: Divide both sides by -7.
−7z
/−7
=
−112
/−7
z=16
Start by putting two coins on each side of the scale. If one side is higher, then the light coin must be in that pair (use a second weighing to determine which of that pair is the lightest.)
If the initial weighing shows the two pairs to be even, discard those four and go to the three others. Put two of the coins on the scale - one on each side. If one side stays higher, that coin is your light one. If however they are equal, the final unweighed coin must be the lighter coin.
I think the answer is c. please tell me if i am right